How Do You Calculate Jerk in Uniform Circular Motion?

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Homework Help Overview

The question involves calculating the jerk of an object in uniform circular motion, focusing on both its direction and magnitude. The discussion revolves around the mathematical representation of motion and the relationships between angular and linear quantities.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the parameterization of circular motion and the differentiation of position to find velocity, acceleration, and jerk. There is uncertainty about expressing results in terms of linear variables like velocity and radius, as well as confusion regarding the relationship between angular velocity and linear motion.

Discussion Status

Some participants have offered guidance on differentiating the parameterized motion and relating angular and linear quantities. There is ongoing exploration of how to express jerk in terms of velocity and radius, with various interpretations of the problem being considered.

Contextual Notes

Participants note that the topic of jerk is being discussed without prior coverage of rotational motion concepts in class, leading to some confusion. There are references to classroom discussions and notes that may not have fully addressed the relationships between angular and linear motion.

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Homework Statement


The question asks to calculate the jerk of an object (both its direction and magnitude) in uniform circular motion.

Homework Equations


j=d(a)/dt

The Attempt at a Solution


I know that the direction is opposite the velocity vector (I did this by drawing a circle and taking a limit of average acceleration as t approaches 0). I also know that the parallel component of jerk is 0 because the parallel component of acceleration in UCM is 0. I am stuck on the magnitude of the perpendicular component. I know that
\vec{a}_{\perp} = \frac{v^2}{2}(-r) (the r is a unit vector)... can I just take the derivative of this? wouldn't that be 0? because v^2/r is a constant and there is no t. i am suck.
 
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Perhaps start with a parameterized version of the motion?

##r(t) = R (cos(\omega t) \vec{i} + sin(\omega t) \vec{j})##

Should be easy enough to differentiate repeatedly...
 
gneill said:
Perhaps start with a parameterized version of the motion?

##r(t) = R (cos(\omega t) \vec{i} + sin(\omega t) \vec{j})##

Should be easy enough to differentiate repeatedly...
where did you get that parameterized version?
 
It's just a conversion from polar form to rectangular form of a circle. x = R cos(θ), y = R sin(θ), where θ = ωt to make it time dependent.
 
gneill said:
It's just a conversion from polar form to rectangular form of a circle. x = R cos(θ), y = R sin(θ), where θ = ωt to make it time dependent.
ok so, j_x = Rw^3sin(wt) and j_y = -Rw^3cos(wt) right?

the problem is however that my prof wanted us to express it interms of v and r. i don't really know how to convert from w to r... we haven't really talked about w yet.
 
It seems strange that you'd be learning about a concept like jerk without having covered the basics of rotational motion.

##v = \omega r~~ ; ~~a = \alpha r## are the basic relationships between angular and linear velocities and accelerations. You would profit from taking the magnitudes of each of the vectors along the differentiation path: position → velocity → acceleration → jerk. For example, the magnitude of the velocity vector is v = ω R.
 
gneill said:
It seems strange that you'd be learning about a concept like jerk without having covered the basics of rotational motion.

##v = \omega r~~ ; ~~a = \alpha r## are the basic relationships between angular and linear velocities and accelerations. You would profit from taking the magnitudes of each of the vectors along the differentiation path: position → velocity → acceleration → jerk. For example, the magnitude of the velocity vector is v = ω R.
yeah, it was just one problem out of a list of 10 or so. our teacher kinda talked about w in the last 5 minutes of class on friday, but we haven't touched rotations yet... we haven't even begun f=ma (school just started)
 
toesockshoe said:
the problem is however that my prof wanted us to express it interms of v and r. i don't really know how to convert from w to r... we haven't really talked about w yet.

toesockshoe said:
our teacher kinda talked about w in the last 5 minutes of class on friday,

Did your teacher mention that v2/r = rw2?

Most classes have reading assignments in addition to classroom lectures, so maybe it's discussed in more depth there.
 
Mister T said:
Did your teacher mention that v2/r = rw2?

Most classes have reading assignments in addition to classroom lectures, so maybe it's discussed in more depth there.
he wrote on the board that v=ds/dt = r d(theta)/dt ... and d(theta)/dt is the same as w. that is all he talked/wrote about w. so sorry Mister T... it was hidden in my notes... i guess he did write an equation relating the 2.
 
  • #10
toesockshoe said:
ok so, j_x = Rw^3sin(wt) and j_y = -Rw^3cos(wt) right?

Right. So looking at the x-components and the y-components of the position vector and the acceleration vector, what can you conclude about the direction of those two vectors?

Now make the same comparison of the velocity vector and the jerk vector.

Can you find the magnitude of these vectors from their components?

These should lead you to being able to describe the magnitude and direction of the jerk vector, which is what your teacher is asking you to do.
 

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