How Do You Calculate Mass and Acceleration in a Spring Mass System?

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SUMMARY

The discussion focuses on calculating mass and acceleration in a spring-mass system with a spring constant of 2.56 N/m and a frequency of 0.148 Hz. The mass of the object is determined to be 2.96 kg using the formula m = Tk/4π², where T is the period calculated as T = 1/f. For acceleration, the correct formula a = -kx/m is confirmed, where x is the displacement from the equilibrium position.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Knowledge of harmonic motion and frequency calculations
  • Familiarity with the concepts of mass and acceleration
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of the period of a spring-mass system
  • Learn about the implications of Hooke's Law in real-world applications
  • Explore advanced topics in oscillatory motion and damping effects
  • Investigate the relationship between frequency and energy in spring systems
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Students in physics, engineering, or anyone studying dynamics and oscillatory systems will benefit from this discussion.

Ahmad786
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Homework Statement



An object suspended from a spring with a spring constant of 2.56 N/m vibrates with a frequency of 0.148 Hz
a. What is the mass of the object
b. What is the acceleration of the object at a displacement of -0.120m from the equilibriam position

Homework Equations


a. T=2pi[tex]\sqrt{}m/k[/tex] m=Tk/4pi2' T=1/f
b. a=-kx/m ?

The Attempt at a Solution


a.T=1/f T=1/0.148Hz T=6.756756757s m=Tk/4pi2' m=(6.756756757s)(2.56N/m)/4pi2' m=2.96kg ---- I do not understand if this is right and I think I made a mistake ----
b. I can't figure out what equation to use and how to manipulate it to get an equation for acceleration for the condition
 
Physics news on Phys.org
a. It's right.
b. It's a=-kx/m.
 

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