Acceleration of a spring - mass system

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In the discussion about the acceleration of a spring-mass system, participants explore whether all masses (m1, m2, m3, m4) will have the same acceleration after a string is cut. It is established that the initial extension of both springs can be assumed equal based on the equilibrium position. The conversation highlights the complexity of the system, noting that the extension of the springs may change after the string is cut, affecting the accelerations of the masses. Participants emphasize the need for additional equations to solve for unknowns, particularly the relationship between the masses' accelerations and the tensions in the springs. Ultimately, the discussion revolves around understanding the dynamics of the system post-cut and the implications for spring extensions and mass accelerations.
  • #31
haruspex said:
Yes, but what "constant speed"?
hhmm... I think the value of the speed will be zero because initially object 1 to 3 does not move and no acceleration means that no resultant force acting on it.

So, at the instant the wire is cut, only object 4 will move?

Thanks
 
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  • #32
songoku said:
hhmm... I think the value of the speed will be zero because initially object 1 to 3 does not move and no acceleration means that no resultant force acting on it.

So, at the instant the wire is cut, only object 4 will move?

Thanks
Yes.
 
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  • #33
haruspex said:
Yes.
What if I modify the question a little bit, find the acceleration 2 seconds after the wire is cut?

This is what I have in my mind:
The m4 will push the right spring so the new extension (x3) will be less than x2 and all the other masses will move.

The extension on left spring does not change (still x1) because the left spring, m1 and m2 will move as one system so the acceleration of m1 and m2 will be the same.

This means that the left spring will behave just like an inelastic string.

The magnitude of a1, a2 and a3 will always be the same but all the acceleration, including a4 won't be constant because there is continuous change in the extension of right spring, therefore there is continuous change in restoring force and there is continuous change in resultant force.

Am I correct?

If yes, how to set up equation of m4 to account for continuous change in acceleration?

Thanks
 
  • #34
songoku said:
What if I modify the question a little bit, find the acceleration 2 seconds after the wire is cut?
Then you will need to have unknowns for the positions of three of the four masses independently (m1 and m3 will have a fixed relationship) and write the differential equations relating them. It is safe to assume there will be SHM involved, but it might be quite complicated.
 
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  • #35
haruspex said:
Then you will need to have unknowns for the positions of three of the four masses independently (m1 and m3 will have a fixed relationship) and write the differential equations relating them. It is safe to assume there will be SHM involved, but it might be quite complicated.
Ok then I will leave it for now

Thank you very much for all the help BvU, haruspex, vela
 
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