Acceleration of a spring - mass system

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
34 replies · 3K views
haruspex said:
Yes, but what "constant speed"?
hhmm... I think the value of the speed will be zero because initially object 1 to 3 does not move and no acceleration means that no resultant force acting on it.

So, at the instant the wire is cut, only object 4 will move?

Thanks
 
Physics news on Phys.org
songoku said:
hhmm... I think the value of the speed will be zero because initially object 1 to 3 does not move and no acceleration means that no resultant force acting on it.

So, at the instant the wire is cut, only object 4 will move?

Thanks
Yes.
 
  • Like
Likes   Reactions: songoku
haruspex said:
Yes.
What if I modify the question a little bit, find the acceleration 2 seconds after the wire is cut?

This is what I have in my mind:
The m4 will push the right spring so the new extension (x3) will be less than x2 and all the other masses will move.

The extension on left spring does not change (still x1) because the left spring, m1 and m2 will move as one system so the acceleration of m1 and m2 will be the same.

This means that the left spring will behave just like an inelastic string.

The magnitude of a1, a2 and a3 will always be the same but all the acceleration, including a4 won't be constant because there is continuous change in the extension of right spring, therefore there is continuous change in restoring force and there is continuous change in resultant force.

Am I correct?

If yes, how to set up equation of m4 to account for continuous change in acceleration?

Thanks
 
songoku said:
What if I modify the question a little bit, find the acceleration 2 seconds after the wire is cut?
Then you will need to have unknowns for the positions of three of the four masses independently (m1 and m3 will have a fixed relationship) and write the differential equations relating them. It is safe to assume there will be SHM involved, but it might be quite complicated.
 
  • Like
Likes   Reactions: songoku
haruspex said:
Then you will need to have unknowns for the positions of three of the four masses independently (m1 and m3 will have a fixed relationship) and write the differential equations relating them. It is safe to assume there will be SHM involved, but it might be quite complicated.
Ok then I will leave it for now

Thank you very much for all the help BvU, haruspex, vela
 
  • Like
Likes   Reactions: BvU