Arunachaleshwar Messages 1 Reaction score 0 Thread starter Jan 4, 2015 #1 Find 'n' using permutations: 1/4! + 1/5! + 1/6! = n/7!
chisigma Gold Member MHB Messages 1,627 Reaction score 0 Jan 4, 2015 #2 Arunachaleshwar said: 1/4! + 1/5! + 1/6! = n/7! Welcome on MHB Arunachaleshwar!... ... the problem You propose is not 'impossible'... multiplying the two sides for 7! You have... $\displaystyle n= 7 \cdot 6 \cdot 5 + 7 \cdot 6 + 7 = 259$ ... can it be that You are sending an encrypted message in which the number 259 has a special meaning? ... Kind regards $\chi$ $\sigma$
Arunachaleshwar said: 1/4! + 1/5! + 1/6! = n/7! Welcome on MHB Arunachaleshwar!... ... the problem You propose is not 'impossible'... multiplying the two sides for 7! You have... $\displaystyle n= 7 \cdot 6 \cdot 5 + 7 \cdot 6 + 7 = 259$ ... can it be that You are sending an encrypted message in which the number 259 has a special meaning? ... Kind regards $\chi$ $\sigma$