How Do You Calculate Permutations for Complex Problems?

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SUMMARY

The discussion focuses on calculating permutations for complex problems, specifically arriving at a total of 28 ways to fill in blanks using the formulae 3P1 and 4P1. Participants detail their approaches, including filling in combinations of numbers and utilizing permutation notation. The calculations confirm that both methods yield the same result of 28, demonstrating the consistency of permutation principles in combinatorial problems.

PREREQUISITES
  • Understanding of permutations, specifically the notation 3P1 and 4P1.
  • Basic knowledge of combinatorial mathematics.
  • Familiarity with mathematical problem-solving techniques.
  • Ability to interpret and manipulate mathematical expressions.
NEXT STEPS
  • Study advanced combinatorial techniques, including combinations and variations.
  • Learn about factorial notation and its applications in permutations.
  • Explore real-world applications of permutations in fields like statistics and computer science.
  • Practice solving complex permutation problems using different approaches.
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Mathematicians, students studying combinatorics, educators teaching mathematical concepts, and anyone interested in solving complex permutation problems.

chwala
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Homework Statement
How many even numbers less than ##500## can be formed using the digits; ##[1,2,3,4,5]?## Each digit may be used only once in any number
Relevant Equations
Permutations
Tricky questions ;

Ok in my approach;

[..., .... , ...2...] This can be filled in ##3×3×1=9## ways

[..., .... , ...4...] This can be filled in ##3×3×1=9## ways

[.... , ...4...] This can be filled in ##4×1=4## ways

[.... , ...2...] This can be filled in ##4×1=4## ways

[2] This can be filled in ##1## way

[4] This can be filled in ##1## way

Therefore number of ways is ##9+9+4+4+1+1=28## ways...

Alternatively, i was thinking of the following possibilities;

4,..., 2 The blank can be filled in ##3P1×1## ways

1,..., 2/4 The blank can be filled in ##3P1×2## ways

2,..., 4 The blank can be filled in ##3P1×1## ways

3,..., 2/4 The blank can be filled in ##3P1×2## ways

This will give us; ##3P1×6=18## ways +

[.... , ...4...] This can be filled in ##4×1=4## ways

[.... , ...2...] This can be filled in ##4×1=4## ways

[2] This can be filled in ##1## way

[4] This can be filled in ##1## way

##18+10=28##

The text gives solution only as ##28.##

Your input highly appreciated. This is one of my less favorite topic...:wink:
 
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You can easily write down all fourteen numbers that end in ##2## and check your counting for each category.
 

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