How Do You Calculate pH and [OH-] for a Mixed NH3 and NH4Cl Solution?

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To calculate the pH and [OH-] for a mixed NH3 and NH4Cl solution, the Henderson-Hasselbalch equation can be applied, using the pKa derived from the given Kb of NH3. The initial moles of NH3 and NH4Cl are both 0.1 moles after mixing 500ml of 0.20M solutions. The participant calculated pH values of 5.13 using the normal method and 9.25 using the Henderson-Hasselbalch equation, leading to confusion about which method is appropriate. A suggestion was made to solve the full quadratic equation using the ICE table method for more accurate results. Clarification on the correct approach is sought to resolve the discrepancies in pH calculations.
Alex Santos
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Homework Statement

[/B]
NH3(aq) is a weak base with Kb = 1.8*10-5, Calculate [OH-] in a solution that is made by mixing togeather 500ml of 0.20M NH3(aq) and 500ml of 0.20M NH4CL(aq), what is the value of Ph?

Homework Equations


Henderson Hasselbalch: ph = Pka + log([conj.base/acid])
As well as another approach on the example, the regular one.

The Attempt at a Solution


To start with I am always a bit confused on how to set up the example and giving me the right inital values, for example I have NH4Cl---->NH3 + Cl + H. Now can I use my initial values, as NH3 in terms of moles
moles NH4Cl: 0.5L*0.2M = 0.1 moles
moles NH3: 0.5*0.2M = 0.1moles

using the " normal method" I get PH = 5.13 and by using the Hendersone Hasselbalch I get PH = 9.25.

I will send an attachment of my calculation because I write everything on an Ipad, so you can see clearly what I am doing.
Please correct me and tell me what is wrong and which method is wrong in my case.
Thank you
 

Attachments

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Solve full quadratic for the ICE table method.
 

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