How Do You Calculate Position from Velocity at Time t?

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SUMMARY

The discussion focuses on calculating the position of a body over time given its velocity function, specifically \( v(t) = \sin(\pi t) \). The initial position is set at \( s(0) = 20 \). The integral of the velocity function yields the position function \( s(t) = -\frac{1}{\pi}\cos(\pi t) + 20 + \frac{1}{\pi} \). This confirms that the derivative of the position function \( s'(t) \) equals the velocity function \( v(t) \).

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karush
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$\tiny{205.o27.12 }$
$\text{Given the velocity $v=\frac{ds}{dt}$}$
$\text{and the initial position of a body moving along a
coordinate line,}$
$\text{find the body's position at time t}$
\begin{align}
\displaystyle
v&=\sin\left({\pi t}\right) &s(0)&=20 \\
v'&=\cos{(\pi t)} \\
s(t)&=
\end{align}
$\text{lost.. } $
 
Last edited:
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I think it's like this:

$$s(t)=\int\sin(\pi t)\,\text{d}t=-\frac1\pi\cos(\pi t)+C$$

$$s(0)=-\frac1\pi+C=20\implies C=20+\frac1\pi$$

$$s(t)=-\frac1\pi\cos(\pi t)+20+\frac1\pi$$
 
so $$s'(t)=v(t)$$

;)
 

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