Am I using the right limits on this triple integral?

oliverkahn
Messages
27
Reaction score
2
Let:

\begin{align}
r&=\sqrt{a^2 + p^2 - 2ap \cos \theta}\\
s&=a\\
t&=p\\
f(r) &= \text{continuous function of } r\\
g(s) &= \text{continuous function of } s\\
\end{align}

Consider the expression:

\begin{align}
\int_{q'}^q \int_{b'}^b g(s)\ \int_{s-t}^{s+t} f(r)\ dr\ ds\ dt\
\end{align}

We next have to change the variables from ##(r,s,t)## to ##(\theta, a, p)##. The Jacobian of the coordinate transformation (after computing) is:

##J= \dfrac{\partial r}{\partial \theta}=\dfrac{a\ p\ \sin\theta}{r}##

Thus our new function becomes ##J\ f(r) =\dfrac{a\ p\ \sin\theta}{r} f(r)##

Question:

One of my friends said that the limits of the integration would be as follows:

\begin{align}
\int_{q'}^q \int_{b'}^b g(a)\ \int_{0}^{\pi} \dfrac{a\ p\ \sin\theta}{r} f(r) \ d \theta\ da\ dp\
\end{align}

Is he correct?
 
If you look at it geometrically, r, a, p are lengths of three sides of a triangle, with r opposite ##\theta##. The limits on r are for the two other sides subtracting or adding, which is equivalent to ##\theta## being 0 or ##\pi##. Your friend is correct.
 
  • Like
Likes   Reactions: oliverkahn and berkeman

Similar threads

  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K