Am I using the right limits on this triple integral?

In summary, the conversation discusses a coordinate transformation and the resulting Jacobian, as well as the correct limits for an integration involving r, a, and p. The limits for the integration are determined geometrically and are correctly stated by the friend.
  • #1
oliverkahn
27
2
Let:

\begin{align}
r&=\sqrt{a^2 + p^2 - 2ap \cos \theta}\\
s&=a\\
t&=p\\
f(r) &= \text{continuous function of } r\\
g(s) &= \text{continuous function of } s\\
\end{align}

Consider the expression:

\begin{align}
\int_{q'}^q \int_{b'}^b g(s)\ \int_{s-t}^{s+t} f(r)\ dr\ ds\ dt\
\end{align}

We next have to change the variables from ##(r,s,t)## to ##(\theta, a, p)##. The Jacobian of the coordinate transformation (after computing) is:

##J= \dfrac{\partial r}{\partial \theta}=\dfrac{a\ p\ \sin\theta}{r}##

Thus our new function becomes ##J\ f(r) =\dfrac{a\ p\ \sin\theta}{r} f(r)##

Question:

One of my friends said that the limits of the integration would be as follows:

\begin{align}
\int_{q'}^q \int_{b'}^b g(a)\ \int_{0}^{\pi} \dfrac{a\ p\ \sin\theta}{r} f(r) \ d \theta\ da\ dp\
\end{align}

Is he correct?
 
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  • #2
If you look at it geometrically, r, a, p are lengths of three sides of a triangle, with r opposite ##\theta##. The limits on r are for the two other sides subtracting or adding, which is equivalent to ##\theta## being 0 or ##\pi##. Your friend is correct.
 
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