How Do You Calculate Rider Speed and Safety on a Centrifuge Carnival Ride?

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SUMMARY

The discussion focuses on calculating rider speed and safety on a centrifuge carnival ride with a diameter of 4.8 meters and a rotation period of 5.0 seconds. The speed of the rider is determined using the formula v = (2πr)/T, resulting in a speed of 6.0 m/s. The centripetal acceleration is calculated as Ac = (v²)/r, yielding a value of 15 m/s². Additionally, the coefficient of friction necessary to prevent slipping is derived from the relationship between centripetal force and frictional force, emphasizing the importance of understanding force diagrams.

PREREQUISITES
  • Understanding of circular motion and centripetal force
  • Familiarity with basic physics equations, specifically v = (2πr)/T
  • Knowledge of frictional forces and their calculations
  • Ability to draw and interpret force diagrams
NEXT STEPS
  • Research the derivation of centripetal acceleration formulas
  • Study the relationship between frictional force and normal force in detail
  • Learn about the effects of ride design on rider safety
  • Explore advanced topics in rotational dynamics and their applications in amusement rides
USEFUL FOR

Physics students, ride engineers, safety analysts, and anyone involved in the design and operation of amusement park rides.

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Homework Statement


A ride has a diameter of 4.8 N and makes 2 complete rotations in 5.0s.
a) Determine the speed of the rider.
b)What is the centripetal acceleration of the rider?
c) What is the coefficient of friction required to keep the rider from slipping downwards when the floor drops down?


Homework Equations


v= (2\pir)/T
Fc=MAc
coefficient of friction=F/N


The Attempt at a Solution


a) v= (2\pi2.4)/2.5s
=6.0
b) Ac= (6s)2/2.4m
=15
c) I don't get how to get this...
 
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Draw a force diagram.

You have the weight down = m*g

You have the centripetal force = m*v²/r that is radially outward pressing the rider into the ride.

Now you should also know that the Maximum force of friction is μ * the normal force which is your centripetal force in this case.
 

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