How Do You Calculate Temperature Changes and Heat Requirements in Water?

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SUMMARY

The discussion focuses on calculating temperature changes and heat requirements in water using specific heat capacity. For a mass of 1.00 kg of water losing 83.8 kJ of heat, the temperature decreases by 0.2 degrees Celsius, calculated using the formula 83.8 kJ / 4.19 J * (1.00 kg * 1000). To raise the temperature of 10.0 kg of water by 20.0 degrees Celsius, one must apply the specific heat capacity of water, which is 4.19 J/g°C, factoring in the larger mass and temperature change. The correct approach involves using the equation Q = mcΔT, where Q is heat energy, m is mass, c is specific heat capacity, and ΔT is the change in temperature.

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  • Basic knowledge of thermal energy calculations
  • Ability to convert units (e.g., grams to kilograms)
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demode
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1. How many celsius degrees does the temperature of a mass of 1.00 kg of water fall for each 83.8 kJ of heat it loses.
2. Not so sure about EQUATIONS but I have my own way of going at it.
3. 83.8 kJ / 4.19 J * (1.00 kg * 1000) = 0.2 degrees celsius



1. How much heat is required to raise the temperature of a mass of 10.0 kg of water a total of 20.0 celsius degrees.
2. Not so sure about EQUATIONS but I have my own way of going at it.
3. IF it takes 4.19 j of heat to raise the temperature of 1 gram of water by one degree celsius, how do we factor in the larger mass of 10,000 grams and the larger temperature change of 20 celsius degrees?
 
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Your solution to the first question is correct. For the second, you should consider an equation relating the specific heat capacity of water, its mass and the change in temperature to thermal energy. I'm sure you will have been given some formulae in your notes/text.
 

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