How Do You Calculate Tension and Acceleration in a Two-Crate System?

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Homework Help Overview

The discussion revolves around a physics problem involving two crates on a frictionless surface, where a woman applies a horizontal force to one of the crates. Participants are exploring how to calculate the acceleration of the crates and the tension in the connecting rope.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss drawing free body diagrams to visualize forces acting on the crates and the woman. There is uncertainty about how to represent these forces and how to calculate acceleration when multiple masses are involved. Some participants suggest that the acceleration could be the same for both crates, while others question the calculations and units used.

Discussion Status

Some participants have provided guidance on the calculations, noting that the acceleration should be expressed in meters per second squared and that the tension in the rope is equal to the applied force. However, there remains some confusion regarding the units and the setup of the problem.

Contextual Notes

Participants are working under a time constraint to complete the homework, and there is a mention of a lack of clarity in class regarding how to approach the tension calculation.

~christina~
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Homework Statement


2 crates shown in the figure below are on a horizontal frictionless surface. The woman is wearing golf shoes for traction as she applies a horizontal force of f= 50.0 N to the 6.00kg crate. The ropes are of negligible mass.

a) draw a free body diagram for each of the crates and the woman and for each force, indicate what body exerts that force.

b) What is the acceleration of the 6.00kg crate?

c) what is the tension T in the rope connecting the 2 crates.


http://img265.imageshack.us/img265/8195/picture2xo8.th.png

Homework Equations



F= ma

I don't know the equation for tension though...

The Attempt at a Solution



Well would the free body diagram show the forces going in different directions?
I assume so but for the other box and woman how would that look?

b.) F= ma
I know it's that equation but how do I find out how much is the acceleration since there are 2 boxes but I have to find the acceleration of the first one?
do I add the masses and assume that the acceleration is the same for both? I think that it would be logical ..so

F= 50N
a=?
m= smaller box + larger box = 4.00kg + 6.00kg= 10.00kg= 10,000g

F= ma
50N= 10,000g*a

a= 5e-3m/s^2

Is this correct?
__________________________________________________
c.) for this part I have no idea how to find tension since it wasn't explained in class.



~Thanks~

P.S I really need to do this question by today...
 
Last edited by a moderator:
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for the woman, it would be 50N on to the left(thats how much she applies) n 50N to right(thats frictional force, remember she doesn't move).
for the other box, only force acting is tension towards right(thats why it accelerates)

your solution to B) is correct

its the same as applied by the woman, ie 50N
 
oh no, look for the units in your calculations, i missed them in first go
 
So is the units incorrect or the problem??

so there isn't any calculation for tension?? it's just 50 N??


and wouldn't the acceleration be in m/s^2...why is it incorrect?
 
Can someone PLEASE help me with this question?? I need to finish this question by today and I need help...or at least I think I do

~Thanks a lot~
 
F is kg*m*s^(-2).
acceleration is m*s^(-2)
so mass should be in Kg, not in "grams", as you have taken
and thus acceleration comes out to be (with a lil help from my calculator) as 5m/s^2

also tension is equal to the force applied, so 50N
 
Oh okay Thanks for clearing that up for me =D
 

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