How Do You Calculate the Acceleration of a 42kg Ice Block Sliding Down a Slope?

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SUMMARY

The acceleration of a 42 kg ice block sliding down a 30-degree slope, assuming negligible friction, can be calculated using the formula Fnet = max. The weight of the block is determined by multiplying its mass (42 kg) by the acceleration due to gravity (9.8 m/s²), resulting in a weight of 411.6 N. The net force acting on the block in the x-direction is derived from the x-component of the weight, which is responsible for the acceleration down the incline.

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet = max)
  • Knowledge of gravitational force calculation (W = mg)
  • Basic trigonometry for resolving forces on an incline
  • Familiarity with free body diagrams
NEXT STEPS
  • Learn how to resolve forces on inclined planes using trigonometric functions
  • Study the effects of friction on acceleration in inclined motion
  • Explore the concept of normal force and its role in motion on slopes
  • Investigate real-world applications of inclined plane physics in engineering
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators looking for examples of force resolution and acceleration calculations.

dhymas
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Urgent! Acceleration of an ice block given mass

Homework Statement


A 42 kg block of ice slides down a slope of 30 degrees. Assuming friction is negligible, what is the acceleration of the block down the incline?


Homework Equations


Fnet=max
W=mg



The Attempt at a Solution


I have drawn a free body diagram correctly. I have the block on a slope of 30 degrees. I have weight acting downward and Normal Force acting perpendicular to the slope. I just want to make sure that I am doing this right.

Fnet=max
I know I have mass already and I can get weight by multiplying 42 by 9.8 m/s2
My problem is what numbers would I use for Fnet? Just the X component for weight or also the Y component?
 
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What you want to be sure to do is label the x-axis as the axis parallel to the incline, and the y-axis as the axis perpendicular to the incline. In this manner, there will be no acceleration along the y-axis because the block does not move in that 'y' direction (it doesn't jump off the plane because the weight component in the 'y' direction is balanced by the normal force in the 'y' direction). So what is the net force acting in the 'x' direction and what is its magnitude?
 

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