How Do You Calculate the Angular Momentum of a Rotating Bat?

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SUMMARY

The discussion focuses on calculating the angular momentum of a rotating bat, specifically a 0.9 m long bat with a mass of 0.6 kg rotating at 3 rad/s. The correct approach involves using the moment of inertia for a long thin cylinder, which is essential for accurate calculations. The formula for angular momentum is L = Iω, where I is the moment of inertia and ω is the angular velocity. The initial attempt incorrectly applied the moment of inertia formula, leading to an incorrect result.

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Homework Statement


A batter swings a 0.9 m long bat. Calculate the angular momentum of the bat relative to its axis of rotation. Assume the bat has a mass of 0.6 kg and rotates at 3 rad / s
(Hint: Approximate the bat by a rod, or a long thin cylinder, and find the moment of inertia.)
Answer in (N m)

Homework Equations


I=mr^2
ω=v/r
v=ωr
L=Iω

The Attempt at a Solution


L=Iω
I=mr^2
so L=(0.6)(.9^2)(ω)
ω=angular velocity is 3 rad/s
so L=(.6)(.9^2)(3rad/s)= Wrong answer
 
Last edited:
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Hey, welcome to physicsforums!
uh, the moment of inertia formula you have used is not correct for this problem. The inertia I=(0.6)(0.9)^2 would suggest the mass of the bat is concentrated at the end of the bat. But it looks like they want you to assume the bat is a long thin cylinder, of uniform density. So either you can look up the moment of inertia for this kind of object, or derive it yourself, if you have time.
 
BruceW said:
Hey, welcome to physicsforums!
uh, the moment of inertia formula you have used is not correct for this problem. The inertia I=(0.6)(0.9)^2 would suggest the mass of the bat is concentrated at the end of the bat. But it looks like they want you to assume the bat is a long thin cylinder, of uniform density. So either you can look up the moment of inertia for this kind of object, or derive it yourself, if you have time.
Thanks!
I got it I was using the wrong formula.
 

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