How Do You Calculate the Distance Traveled in the Last Second of Acceleration?

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SUMMARY

The discussion focuses on calculating the distance traveled by a plane during the twelfth second of acceleration, given that it accelerates from rest and covers 600 meters in 12 seconds. The relevant equations are d = v0t + 1/2at² and v = v0 + at. The solution involves determining the position of the plane at t=11 seconds and t=12 seconds to find the distance covered in the last second. The user successfully calculated acceleration and final speed but needed assistance with the specific calculation for the twelfth second.

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Homework Statement



A plane starts from rest and accelerates in a straight line along the ground before takeoff. It moves 600m in 12s. Find a) acceleration, b) speed at the end of 12s, c) the distance moved during the twelfth second.

Homework Equations


d = volt + 1/2at^2

v = volt + at


The Attempt at a Solution



I got the answers to part a and b, but not to part c. I feel stupid, I've been staring at this part for awhile. Things are not registering...:frown:

Do i use the first equation?

someone please help!
 
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This is the distance traveled during one second between t1=11 s and t2=12 s time. You can use the first equation to get where was the plane at the end of the 11th second and where is it at the end of the 12th second. ehild
 

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