How Do You Calculate the Molarity of Glacial Acetic Acid?

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Discussion Overview

The discussion revolves around calculating the molarity of glacial acetic acid, focusing on its density, composition, and the definition of molarity. Participants explore the implications of the high percentage of acetic acid in the solution and how it affects the calculation.

Discussion Character

  • Homework-related
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant seeks clarification on whether molarity refers to the total number of moles or just the moles of acetic acid in glacial acetic acid.
  • Another participant questions if glacial acetic acid can be considered a solution given its high purity (99.51% acetic acid) and the small percentage of other substances.
  • Some participants assert that the 0.49% of other substances is negligible for the purpose of calculating molarity, while others suggest it should still be acknowledged in the calculation.
  • A participant emphasizes that the definition of molarity can apply to pure substances, such as pure water, indicating a broader interpretation of the concept.
  • There is a suggestion to calculate the number of moles of CH3COOH in 1000 mL of glacial acetic acid to determine its molarity, clarifying that only the moles of acetic acid are relevant.

Areas of Agreement / Disagreement

Participants express differing views on whether the small percentage of non-acetic acid components should be considered in the molarity calculation. There is no consensus on the implications of this percentage for the definition of molarity in this context.

Contextual Notes

Participants highlight the importance of understanding the definition of molarity and its application to solutions with high purity, but there are unresolved questions regarding the treatment of minor components in the calculation.

Who May Find This Useful

This discussion may be useful for students preparing for chemistry exams, particularly those focusing on solution chemistry and molarity calculations.

alingy1
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Homework Statement



Glacial acetic acid has a density of 1.05g/ml and contains 99.51%acetic acid (CH3COOH) by mass. Calculate the molarity of glacial acetic acid.

So, this is a question in my pre-lab that doesn't even count. But, I still want to get it because we have similar questions in exams.

I'm blocked at the first step:
What is molarity?
Is is the total number of moles? or just the number of acetic acid moles?
 
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It doesn't really help. I'm asking to know if glacial acetic acid is a solution per se. What is the small percentage that makes CH3COOH account for 99.51%? And is that substance taken into any account when you do the calculation of molarity.
 
alingy1 said:
It doesn't really help. I'm asking to know if glacial acetic acid is a solution per se. What is the small percentage that makes CH3COOH account for 99.51%? And is that substance taken into any account when you do the calculation of molarity.

Did you look at the definition of molarity? We aren't concerned with 0.49% but that will be used when calculating molarity. Have a look at the definition, you will get some idea to begin with.
 
Also, if you take a look at the definition, you can apply it even to pure water - that's a very similar situation.
 
Do you know how to find the number of moles of CH3COOH in 1000 mL of glacial acetic acid? That is the same as the molarity.
What is molarity?
moles of constituent (CH3COOH here)/ Liters of solution (glacial acetic acid here)
Is is the total number of moles? or just the number of acetic acid moles?
Only acetic acid.
 

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