- #1

PVnRT81

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## Homework Statement

Calculate the molar neutralization heat of nitric acid (HNO3) using the following data:

**Before Neutralization:**

HNO3 (0.5 mol/L)

V = 200 ml

T= 23 Celsius

LiOH (1 mol/L)

V = 200 mL

T = 25 Celsius

After Neutralization:

After Neutralization:

V = 400 mL

T = 27.5 Celsius

**2. The attempt at a solution**

Calculating the total heat released by Nitric Acid:

q=mcDT

= (400)(4.184)(27.5-23)

= 7531.2 Joules

Calculating moles of Nitric Acid:

C= n/v

(0.5 mol/L) x (0.2) = 0.1 moles Nitric Acid

Calculating Molar Heat of Neutralization:

= (-7532.2 Joules / 1000) / (0.1 moles)

= -75 KJ / mol

Can someone please verify if this is done correctly? Thank you.