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PVnRT81
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Homework Statement
Calculate the molar neutralization heat of nitric acid (HNO3) using the following data:
Before Neutralization:
HNO3 (0.5 mol/L)
V = 200 ml
T= 23 Celsius
LiOH (1 mol/L)
V = 200 mL
T = 25 Celsius
After Neutralization:
V = 400 mL
T = 27.5 Celsius
2. The attempt at a solution
Calculating the total heat released by Nitric Acid:
q=mcDT
= (400)(4.184)(27.5-23)
= 7531.2 Joules
Calculating moles of Nitric Acid:
C= n/v
(0.5 mol/L) x (0.2) = 0.1 moles Nitric Acid
Calculating Molar Heat of Neutralization:
= (-7532.2 Joules / 1000) / (0.1 moles)
= -75 KJ / mol
Can someone please verify if this is done correctly? Thank you.