How Do You Calculate the Moles of H₂SO₄ Needed for a Reaction?

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Discussion Overview

The discussion revolves around calculating the number of moles of sulfuric acid (H₂SO₄) required to react with a diluted sodium hydroxide (NaOH) solution. Participants explore concepts related to molarity, dilution, and stoichiometry in the context of a chemical reaction.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a scenario involving 25 cm³ of NaOH with a molarity of 0.1 mol/dm³, diluted to 250 cm³, and seeks to find the moles of H₂SO₄ needed for a reaction with 30.0 cm³ of this solution.
  • Another participant suggests that the reaction between H₂SO₄ and NaOH is not 1:1, but rather 1:2, prompting questions about the calculations made.
  • Several participants express uncertainty about the correctness of the calculated moles of H₂SO₄, with one participant stating they calculated 0.0003 moles but are unsure if this is accurate.
  • There are repeated requests for clarification on the stoichiometry of the reaction and whether the calculations have accounted for the correct ratio of reactants.
  • One participant advises writing the reaction equation and calculating the moles of NaOH to determine the moles of H₂SO₄ using stoichiometry.

Areas of Agreement / Disagreement

Participants disagree on the correctness of the initial calculation of moles of H₂SO₄, with some asserting that the calculation is incorrect due to the stoichiometric ratio of the reaction. The discussion remains unresolved regarding the accuracy of the calculations presented.

Contextual Notes

Participants have not fully detailed their assumptions or the steps taken in their calculations, leading to potential gaps in understanding the stoichiometric relationships involved.

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thread moved from technical forum: please ask HW questions in the HW forums, filling the template and showing your work
TL;DR Summary: Question about molarity and concconcentration

25 cm^(3) of NaOH solution with the molarity of 0.1moldm^(-3) Was measured to a pipette and added to a volumetric flask. Then by adding distilled water to the solution, the solution is diluted until the total volume is 250cm^(3) Find the number of moles of H₂SO required to react with 30.0cm(3) of the solution thus made.
 
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What is your own attempt?
 
Mayhem said:
What is your own attempt?
0.0003 mol
Mayhem said:
What is your own attempt?
 
Adheesha said:
TL;DR Summary: Question about molarity and concconcentration

25 cm^(3) of NaOH solution with the molarity of 0.1moldm^(-3) Was measured to a pipette and added to a volumetric flask. Then by adding distilled water to the solution, the solution is diluted until the total volume is 250cm^(3) Find the number of moles of H₂SO required to react with 30.0cm(3) of the solution thus made.
The answer I got is 0.0003 mol.I just wanna know whether it's correct or not cuz I'm not sure about my answer
 
Assuming you meant H2SO4 - does it react 1:1 with NaOH?
 
Borek said:
Assuming you meant H2SO4 - does it react 1:1 with NaOH?
NO.It reacts 1:2 with NaOH
 
Have you accounted for that?
 
Borek said:
Assuming you meant H2SO4 - does it react 1:1 with NaOH?
NO.It reacts 1:2 with NaO
Borek said:
Have you accounted for that?
I tried to solve the question and the answer I got was 0.0003 moles.can anybody tell me whether it's correct or not?
 
No, it is not correct, and I already pointed you to a reason why it is wrong.

Write reaction equation, calculate number of moles of NaOH, use the stoichiometry to calculate number of moles of H2SO4.
 
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Borek said:
No, it is not correct, and I already pointed you to a reason why it is wrong.

Write reaction equation, calculate number of moles of NaOH, use the stoichiometry to calculate number of moles of H2SO4.
Ok thank you
 

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