How Do You Calculate the Moment of Inertia for a Tube?

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SUMMARY

The moment of inertia for a tube can be calculated using the formula I = (1/4)M(R1^2 - R2^2) + (1/3)ML^2, where M is mass, R1 and R2 are the outer and inner radii, and L is the length of the tube. Users discussed various methods to derive this formula, emphasizing the importance of integration and understanding the physical principles behind moment of inertia. Additional resources such as Wikipedia and HyperPhysics were recommended for further learning.

PREREQUISITES
  • Understanding of basic physics concepts, particularly rotational dynamics.
  • Familiarity with calculus, specifically integration techniques.
  • Knowledge of the definitions and formulas related to moment of inertia.
  • Ability to interpret mathematical expressions and apply them to physical scenarios.
NEXT STEPS
  • Study the derivation of moment of inertia for various shapes, including cylinders and spheres.
  • Learn about the application of integration in calculating moments of inertia.
  • Explore resources like HyperPhysics for in-depth explanations of rotational inertia.
  • Investigate the relationship between mass distribution and moment of inertia in different geometries.
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Students in physics, engineers working on mechanical systems, and anyone interested in understanding the principles of rotational dynamics and moment of inertia calculations.

chui
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I couldn't find the Moment of inertia of the next tube:

moment.jpg


hope you can help..thnks
 
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What, exactly, did you try to do?
 
I am not a physics student yet, so I don't really know.
By seeing diffrent exempls of moment of inertia I thoght it may be
0.25M(r1^2-r2^2) + 0.25ML^2
But this is only by intuation so I can't actually use it.
please, help me if you can.
 
You will not find the moment of inertia by just guessing. You need a place to start. Do you have a (mathematical) definition for moment of inertia? Have you had any calculus classes? What was the actual assignment?
 
I do'nt think it is an assignment - he wants to build/construct something or work something out without having the necessary Physics background. so either we need to just give hime the answer or direct him to a tutorial.
Chui, start by looking at http://wps.aw.com/aw_young_physics_11. Have a look at Part 1:Mechanics - 7.6 Rotational Inertia.
 
Last edited:
andrevdh

andrevdh rights! (thankyouverymuch)
All I need is the formula, with no other choice, I can develpoe it by myself but it will take time.
I want it for other calculation so I only need a formula.

If anyone know,(or have a book which know) please write it.
thanks.
 
This is the homework section and we're not supposed to "give" the answer without the person showing some work. Otherwise, post in a different section! :)
 
alright, I used Wikipedia, to learn some things with Integration,
but it wasn't enought, I didn't understand too many things yet.
however, I looked here:
http://en.wikipedia.org/wiki/List_of_moments_of_inertia
and learn the next things:
1) an axis located at the center of a solid cylinder , its MomentumOfInertia should be this:
(1/4)MR^2 + (1/12)ML^2 (number 3 on the list)
2) a Rod with its axis on center its I should be:
(1/12)ML^2 (one befort the last one on the list)
3) a Rod with its axis on the end, like I need, its I should be:
(1/3)ML^2 (the last one on the list)
I put it all together with number 2 in the list to get this:
(1/4)M(R1^2-R2^2) + (1/3)ML^2
I still don't sure if I should put a minus or a plus between R1^2
to R2^2
 
  • #10
It will be r_1^2 + r_2^2. That part of the integration gives r_1^4-r_2^4 which factors into (r_1^2-r_2^2)(r_1^2+r_2^2 and the first factor (minus sign) ultimately gets absorbed into M. I don't have time right now but I need to check on that factor of 1/4.
 
  • #11
i'm sorry I don't mean to change the subject, but how would I show that the Rotational Inertia would be 2/5MR^2 of a uniform sphere about any axis. I tried to first calculate the R.I. of a disk but I am not getting anywhere. . . please help if you can? I just became a memeber today and don't know how to post a new thread and this is the only thread relavent to what I need help with. . .
 
  • #12
bluejay,

You need to integrate the square of the distance from the rotation axis. It looks like this:

I = 2\pi \rho \int_0^R r^2 dr \int_0^\pi d\theta r^2 \sin^3 \theta

where the 2\pi if from integrating about the azimuth (based on symmetry). \rho = \frac {M}{4\pi R^3/3} is the mass density. This works out to the desired result.
 

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