How Do You Calculate the Parallel and Perpendicular Components of a Vector?

  • Thread starter Thread starter hadroneater
  • Start date Start date
  • Tags Tags
    Components Vector
Click For Summary
SUMMARY

The discussion focuses on calculating the parallel and perpendicular components of a force vector F = 700[-0.25, 0.433, 0.866] relative to vector A = [-4, 4, 2]. The participants confirm that the dot product is essential for determining these components, using the equations A·F = |A||F|cos(θ) for parallel components and A·B = 0 for perpendicular components. The solution involves expressing vector A in a normalized form and applying the dot product to isolate the parallel component, leading to the conclusion that F_parallel = |F|cos(θ).

PREREQUISITES
  • Understanding of vector operations, specifically dot products
  • Knowledge of vector normalization techniques
  • Familiarity with trigonometric functions in the context of vectors
  • Basic principles of vector decomposition
NEXT STEPS
  • Study vector normalization methods to simplify calculations
  • Learn about vector decomposition techniques in physics
  • Explore the geometric interpretation of dot products in vector analysis
  • Practice problems involving parallel and perpendicular components of vectors
USEFUL FOR

Students in physics or engineering courses, educators teaching vector analysis, and anyone needing to apply vector decomposition in practical scenarios.

hadroneater
Messages
56
Reaction score
0

Homework Statement


force vector F = 700[-0.25, 0.433, 0.866].
vector A = [-4, 4, 2]
a)What is the component of F that is parallel to A?
b}And what is component of F that is perpendicular to A?

Homework Equations


A\bullet F = |A||F|\cos{\theta}
When two vectors are parallel:
A\bullet B = |A||B||
When two vectors are perpendicular
A\bullet B = 0


The Attempt at a Solution


I'm not sure if I should use the dot product to find the component but I figure that would be the simplest way to do so.
A = [-4, 4 ,2] = 6[-2/3, 2/3, 1/3]
The parallel force vector = s[-2/3, 2/3, 1/3]
That's all I have right now. If I use the dot product equation, both sides of the equation will come to the same term and cancel each other out. I think my definition for the parallel force vector is too general as s could be any scalar.
 
Physics news on Phys.org
Note that
<br /> F_{parallel} = |F|\cos{\theta}<br />
(this is obvious if you draw two vectors on paper and apply a little trig)

So
<br /> A\bullet F = |A|F_{parallel}<br />
Then just use the definition of the dot product to calculate the left hand side and solve for the parallel component
 

Similar threads

Replies
26
Views
2K
Replies
10
Views
1K
Replies
26
Views
4K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
11
Views
3K
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K