How Do You Calculate the Probability of Getting at Most One Brown M&M?

  • Context: Undergrad 
  • Thread starter Thread starter r1terrell23
  • Start date Start date
  • Tags Tags
    Binomial Stats
Click For Summary

Discussion Overview

The discussion revolves around calculating the probability of selecting at most one brown M&M from a sample of seven, given that 30% of M&Ms are brown. Participants explore the application of the Binomial Distribution to solve this problem, including specific calculations and corrections to earlier claims.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant initially attempted to use the Binomial Distribution but expressed uncertainty about their approach.
  • Another participant provided calculations for the probabilities of selecting 0 and 1 brown M&M, but later acknowledged a mistake in the probabilities used.
  • A subsequent post corrected the probabilities and provided a revised calculation for P(X=0) and P(X=1) using the Binomial Distribution formula.
  • Participants discussed the parameters for the Binomial Distribution, specifically noting n=7, p=0.3, and q=0.7.

Areas of Agreement / Disagreement

There is no consensus on the correct calculations, as participants provided differing values and corrections throughout the discussion. Multiple competing views remain regarding the proper application of the Binomial Distribution.

Contextual Notes

Participants did not fully resolve the calculations, and there are indications of missing assumptions or misunderstandings regarding the application of the Binomial Distribution.

r1terrell23
Messages
2
Reaction score
0
Okay so I did this problem and got it wrong but I get one more chance to get it right. I tried using Binomial Dist to solve it but I failed.

30% of all M&Ms are brown. If 7 M&Ms are randomly selected, what is the probability that at most 1 is brown?

I thought I would use 0 and 1 but I guess not. Can someone help me?
 
Physics news on Phys.org
p0=.37
p1=7*.36*.7

Add them up.
 
Sorry, got the probs reversed. switch .3 and .7.

p0=.77
p1=7*.76*.3

Add them up.
 
For Binomial Distribution,
take n=7, p=0.3, q=1-p=0.7.

P(X<=1)=P(X=0)+P(X=1)=q^7+n*p*q^6

thts it gys...
enjy
 

Similar threads

  • · Replies 29 ·
Replies
29
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
1
Views
2K
  • · Replies 41 ·
2
Replies
41
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K