How Do You Calculate the Sunset Time on the Winter Solstice at 40 Degrees North?

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To calculate the sunset time on the winter solstice at 40 degrees north latitude, the declination of the sun is -23.5 degrees and the right ascension is 18h. The hour angle of the sun must be determined to find the local apparent solar time, which then needs to be corrected to mean solar time. Spherical trigonometry is essential for setting up the necessary calculations. A recommended resource for hand calculation methods is a specific book that can assist with these types of astronomy problems. Understanding these concepts will aid in accurately determining sunset times.
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Hi everyone, new member here. Anyway, for my astronomy class my professor wants us to calculate the zone time the center of the sun sets on the winter solstice, at 40 degrees north latitude, and I'm a bit stuck. I know on the winter solstice, the declination of the sun is -23.5 degrees and the right ascension is 18h, and since it would be setting the altitude would be zero. I figured out that I need to find the hour angle of the sun at that exact moment, and use this as the local apparent solar time, and correct to make it mean solar time. I think the objective is to use spherical trigonometry and set up a triangle in the sky, but I'm at a loss of how to set it up, so if anyone could give me a few pointers, that would be great. Thanks.
 
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