How Do You Calculate the Velocity of a Counterweight Relative to an Elevator?

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SUMMARY

The discussion focuses on calculating the velocity of a counterweight relative to an elevator, specifically when a winch draws cable at a constant rate of 2 m/s. The correct approach involves understanding the relationship between the winch speed and the elevator's speed, which is determined to be half that of the winch, resulting in an elevator speed of 1 m/s. The equation used, 4Vw + Vc = 0, was identified as incorrect for this scenario, leading to confusion in the calculations. The key takeaway is that the counterweight moves in relation to the elevator and the winch's cable movement must be accurately accounted for.

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Homework Statement



In the sketch at right, the winch W draws the cable at a constant rate of 2 m/s.
Calculate the velocity of the counterweight C relative to the elevator E.

Homework Equations



(Sa-Sc)+(Sb-Sc)+Sb=I2

The Attempt at a Solution



I must be using the wrong equation because I am getting really strange answers.
 

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deveny7 said:
I must be using the wrong equation because I am getting really strange answers.
Perhaps, perhaps not, we're unable to say either way since you haven't included your working for us to see what equation/s you are using.

Q: How fast is the elevator rising?
 
I used 4Vw +Vc = 0. Which means the elevator would rise at 8m/s but that can't be right.
 
Think about it in terms of the amount of rope wound in. If the winch winds in 2m the elevator goes up 1m. So the elevator moves up at half the speed of the winch eg 1m/s

Then look at the elevator and counter weight. If the elevator were raised say 1 meter how far does the counterweight move relative to the platform? How far does it move relative to the elevator?
 

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