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I How do you derive Slater determinant from creation operator?

  1. May 23, 2016 #1

    Could someone provide me with a good proof or explain me here how we can derive Slater determinant for N fermions by starting with the vaccuum state and the creation operators with anticommutation equations. I see that the idea of both these structures is similar but I cannot work it out rigorously.

    Thank you.
  2. jcsd
  3. May 23, 2016 #2

    Charles Link

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    Gordon Baym's book Lectures on Quantum Mechanics covers this in the chapter on Second Quantization. His treatment of it is quite good, other than on occasion he does have a ## \sqrt{n!} ## that should be simply a ## \sqrt{n} ## or similar minor typo. I think the book is currently out of print but very good reading if you can get a copy of it.
  4. May 23, 2016 #3
    Thank you, I will take a look at this chapter.
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