I would write:
$$y=\frac{2x}{x-1}=\frac{2x-2+2}{x-1}=\frac{2(x-1)+2}{x-1}=2+\frac{2}{x-1}$$
We see this will have a horizontal asymptote at $y=2$, and so the range must be:
$$(-\infty,2)\,\cup\,(2,\infty)$$
We know this will have a graph that is the same as $$y=\frac{1}{x}$$, but vertically stretched by a factor of 2 and translated one unit to the right, neither of which affect the range. It will also be translated 2 units up, which will affect the range by moving the horizontal asymptote up 2 units.