How do you determine work done wi th just mass and distance?

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SUMMARY

The discussion focuses on calculating work done using the formula W=Fd, where W represents work, F is force, and d is distance. A specific example involves pushing a 28 kg object over a distance of 1.2 m, leading to confusion about the missing acceleration variable. The correct answer of 1200 J indicates that additional information, such as acceleration or final velocity, is necessary to solve the problem accurately. The participants conclude that without this data, the question remains incomplete.

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crushedcorn
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1. The problem statement, all variables and given/Information

If a person pushes a 28 kg object 1.2 m, how much work did they just do?

Homework Equations


W=Fd
F=ma

The Attempt at a Solution


If W=Fd and F=ma, then W=(ma)d. The farthest I can get is W=28a*1.2=33.6a. Since the motion is horizontal, a=9.8 m/s2 wouldn't apply, so I am left with 2 variables and no answer. However, the correct answer is 1200 J. Where is this answer coming from?
 
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Out of the blue, as they say. Hello CC, and welcome to PF :smile: !

With the given information, there really is no telling. As you more or less conclude correctly.
There must be something else.
 
you would need atleast ##a## or final velocity. because for 1200J a= 35.7m/s², what if i choose a=1m/s². ill get a different answer.
So the question is incomplete.
 
Thank you and thank you! I felt like I was missing the entire concept. I feel much better :-)
 

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