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How do you determine work done wi th just mass and distance?

  1. Mar 20, 2015 #1
    1. The problem statement, all variables and given/Information

    If a person pushes a 28 kg object 1.2 m, how much work did they just do?
    2. Relevant equations
    W=Fd
    F=ma

    3. The attempt at a solution
    If W=Fd and F=ma, then W=(ma)d. The farthest I can get is W=28a*1.2=33.6a. Since the motion is horizontal, a=9.8 m/s2 wouldn't apply, so I am left with 2 variables and no answer. However, the correct answer is 1200 J. Where is this answer coming from?
     
  2. jcsd
  3. Mar 20, 2015 #2

    BvU

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    Out of the blue, as they say. Hello CC, and welcome to PF :smile: !

    With the given information, there really is no telling. As you more or less conclude correctly.
    There must be something else.
     
  4. Mar 20, 2015 #3

    Suraj M

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    you would need atleast ##a## or final velocity. because for 1200J a= 35.7m/s², what if i choose a=1m/s². ill get a different answer.
    So the question is incomplete.
     
  5. Mar 20, 2015 #4
    Thank you and thank you! I felt like I was missing the entire concept. I feel much better :-)
     
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