How Do You Divide Rational Expressions?

  • Context: High School 
  • Thread starter Thread starter tikka
  • Start date Start date
Click For Summary
SUMMARY

This discussion focuses on the process of dividing rational expressions, specifically using the example of (x² - x - 20)/(x² - 6x) divided by (x² + 9x + 20)/(x² - 12x + 36). The method involves polynomial long division, where the highest degree terms are divided first, followed by multiplication and subtraction to find the quotient and remainder. The final simplified expression is (x - 5)(x - 6)/(x(x + 5)), demonstrating the importance of factoring for simplification.

PREREQUISITES
  • Understanding of polynomial long division
  • Familiarity with factoring polynomials
  • Basic knowledge of rational expressions
  • Ability to manipulate algebraic fractions
NEXT STEPS
  • Learn polynomial long division techniques
  • Study factoring methods for quadratic expressions
  • Explore the use of TexAide for mathematical notation
  • Practice simplifying rational expressions through various examples
USEFUL FOR

Students in high school mathematics, particularly those struggling with algebra and rational expressions, as well as educators seeking to provide clear explanations of these concepts.

tikka
Messages
2
Reaction score
0
hello people. I am sorry about this post becuse i have been reading some of the posts here and they are really high lvl math. I however am only in grade 10. I am having troubles dividing rational expressions. I have missed a week or so of school and I am lost now :frown:
. i have an example here that hopefully some one can walk me step by step through it.
Thanks for your time and posts are appreciated.


EX.
x^2 - x - 20 x^2 + 9x + 20
------------- / --------------
x^2 - 6x x^2 - 12x + 36

i can't seem to get them to tay where i put them so the bold is on the right side and the normal is on the left
 
Last edited:
Mathematics news on Phys.org
tikka said:
hello people. I am sorry about this post becuse i have been reading some of the posts here and they are really high lvl math. I however am only in grade 10. I am having troubles dividing rational expressions. I have missed a week or so of school and I am lost now :frown:
. i have an example here that hopefully some one can walk me step by step through it.
Thanks for your time and posts are appreciated.


EX.
x^2 - x - 20 x^2 + 9x + 20
------------- / --------------
x^2 - 6x x^2 - 12x + 36

i can't seem to get them to tay where i put them so the bold is on the right side and the normal is on the left

I have trouble understanding what your expressions mean. However, the general idea of dividing a polynomial by another polynomial is very much like doing long division.

For example (assuming you want (x^2 - x - 20)/(x^2 - 6x)) first look at the highest degree terms in the numerator and the divisor and divide. In this case it is 1. Then multiply the divisor by the trial quotient and subtract from the numerator to get the next trial numerator. Keep going until the trial numerator is of lower degree than the divisor. This last trial numerator is the remainder. In this example, the quotient is 1 and the remainder is 5x - 20.
 
Tikka,

Learn to use tex or TexAide to write (or "type") your expressions to appear in a conventional notated form. TexAide is a free download and is easy to use.

To divide rational expressions, you use the same process as you use for numeric constants - no change. Watch this:

\[<br /> \begin{array}{l}<br /> \frac{{x^2 - x - 20}}{{x^2 - 6x}} \div \frac{{x^2 + 9x + 20}}{{x^2 - 12x + 36}} \\ <br /> \\ <br /> \frac{{x^2 - x - 20}}{{x^2 - 6x}} \bullet \frac{{x^2 - 12x + 36}}{{x^2 + 9x + 20}} \\ <br /> \frac{{(x - 5)(x + 4)}}{{x(x - 6)}} \bullet \frac{{(x - 6)(x - 6)}}{{(x + 4)(x + 5)}} \\ <br /> \end{array}<br /> \]<br />

You see, back factoring any factorable expressions, here you find simplification is possible, or hopefully, helpful.

Then you obtain:

\[<br /> \frac{{(x - 5)(x - 6)}}{{x(x + 5)}} = \frac{{x^2 - 11x + 30}}{{x^2 + 5x}}<br /> \]<br />

Can you take it from there, or still need help? You want to use the expression on the right side, since it is simplified and in a good multiplied form (general forrm).
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K