How do you explain this, Equation?

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Discussion Overview

The discussion centers on the differential equation describing the downward velocity of a person falling with a parachute. Participants explore the physical meaning of the equation and the origins of its variables, particularly in relation to forces acting on the falling individual.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant presents the equation dv/dt = g - (k/m)v and asks how it physically makes sense, specifically questioning the origins of the variables on the right-hand side.
  • Another participant reiterates the equation and explains that in a vacuum, the equation simplifies to dv/dt = g, indicating that the parachute's resistance reduces acceleration, which is represented by the (k/m)v term.
  • A different participant discusses experimental evidence suggesting that air resistance (drag) is approximately proportional to the speed of the object, explaining the negative sign in the equation as a reflection of the opposing forces during downward motion.
  • This participant also derives the equation from the fundamental principle of mass times acceleration equating to total force, leading to the same differential equation.

Areas of Agreement / Disagreement

Participants express different perspectives on the physical interpretation of the equation and its components, indicating that multiple views remain without a consensus on the explanation of the variables involved.

Contextual Notes

The discussion does not resolve the underlying assumptions about the constants involved or the specific conditions under which the equation applies, such as the effects of varying parachute designs or atmospheric conditions.

sl02ggp
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A person who weighs 200 lbs is falling through the sky while attached to a parachute. The equation of the downward velocity as a function of time for this is:

dv/dt = g - (k/m)v

Where g is the acceleration due to gravity, m the person's mass, and k is a constant depending on the physical properties of the parachute.

Question: How does this equation physically make sense? Where does the variables from the ride hand side come from?
 
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sl02ggp said:
A person who weighs 200 lbs is falling through the sky while attached to a parachute. The equation of the downward velocity as a function of time for this is:

dv/dt = g - (k/m)v

Where g is the acceleration due to gravity, m the person's mass, and k is a constant depending on the physical properties of the parachute.

Question: How does this equation physically make sense? Where does the variables from the ride hand side come from?
If the person were falling in a vacuum, the differential equation would be dv/dt = g. The resistance to motion caused by the parachute (and the person's body) will lessen the acceleration, which explains the (k/m)v term being subtracted on the right (not ride) side.

Is that what you're asking about?
 
sl02ggp said:
A person who weighs 200 lbs is falling through the sky while attached to a parachute. The equation of the downward velocity as a function of time for this is:

dv/dt = g - (k/m)v

Where g is the acceleration due to gravity, m the person's mass, and k is a constant depending on the physical properties of the parachute.

Question: How does this equation physically make sense? Where does the variables from the ride hand side come from?
Experimental evidence (which is the final arbiter in "real life" matters) indicates that for an large object moving through air, the air resistance (drag) is, at least approximately, directly proportional to the speed with which the object is moving. 0 speed would mean it is not moving through the air at all so no drag. If the object were moving upward, the resistance would be downward and if the object is moving downward the resistance would be upwared- always opposite to the motion hence the "-".

Starting from "mass times acceleration = total force" we would have m(dv/dt)= mg- kv. Dividing both sides by m, dv/dt= g- (k/m)v.
 

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