How Do You Factor the Fractional Expression [(a + b)^2]/4 - [a^2b^2]/9?

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SUMMARY

The expression \(\frac{(a + b)^2}{4} - \frac{a^2b^2}{9}\) can be factored using the difference of squares method. This is achieved by rewriting the expression as \(\left(\frac{a+b}{2}\right)^2 - \left(\frac{ab}{3}\right)^2\) or \(\frac{1}{36}\left(\left(3(a+b)\right)^2 - (2ab)^2\right)\). Applying the difference of squares formula allows for further simplification and factorization of the expression.

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mathdad
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Factor [(a + b)^2]/4 - [a^2b^2]/9

Can someone get me started?
 
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I would write the expression as the difference of squares:

$$\frac{(a+b)^2}{4}-\frac{a^2b^2}{9}=\left(\frac{a+b}{2}\right)^2-\left(\frac{ab}{3}\right)^2$$

Or, we could write:

$$\frac{(a+b)^2}{4}-\frac{a^2b^2}{9}=\frac{1}{36}\left(\left(3(a+b)\right)^2-(2ab)^2\right)$$

Now apply the difference of squares formula...:D
 
Great. I can take it from here.
 

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