MHB How Do You Factor the Fractional Expression [(a + b)^2]/4 - [a^2b^2]/9?

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The expression [(a + b)^2]/4 - [a^2b^2]/9 can be factored as a difference of squares. It can be rewritten as (1/36)((3(a+b))^2 - (2ab)^2). By applying the difference of squares formula, further simplification can be achieved. This approach provides a clear pathway to factor the given fractional expression effectively. The discussion highlights the importance of recognizing patterns in algebraic expressions for easier manipulation.
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Factor [(a + b)^2]/4 - [a^2b^2]/9

Can someone get me started?
 
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I would write the expression as the difference of squares:

$$\frac{(a+b)^2}{4}-\frac{a^2b^2}{9}=\left(\frac{a+b}{2}\right)^2-\left(\frac{ab}{3}\right)^2$$

Or, we could write:

$$\frac{(a+b)^2}{4}-\frac{a^2b^2}{9}=\frac{1}{36}\left(\left(3(a+b)\right)^2-(2ab)^2\right)$$

Now apply the difference of squares formula...:D
 
Great. I can take it from here.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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