How Do You Find the Laurent Expansion of sin(z)/(z-1) at z=1?

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SUMMARY

The discussion focuses on finding the Laurent expansion of the function sin(z)/(z-1) at the point z=1. The initial approach involves substituting z with 1+h, transforming the function into sin(1+h)/h. This method allows for the expansion of sin(1+h) as a power series in terms of h, facilitating the calculation of the Laurent series around the singularity at z=1. The key takeaway is that expanding sin(z) around z=1 is a valid and effective strategy for deriving the Laurent expansion.

PREREQUISITES
  • Understanding of Laurent series and their applications in complex analysis.
  • Familiarity with power series expansions, particularly for trigonometric functions.
  • Knowledge of the substitution method in complex function analysis.
  • Basic concepts of singularities in complex functions.
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  • Study the properties of Laurent series and their convergence criteria.
  • Learn how to derive power series expansions for trigonometric functions like sin(z).
  • Explore examples of singularities and their classifications in complex analysis.
  • Practice finding Laurent expansions for other functions with singularities.
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Students and professionals in mathematics, particularly those studying complex analysis, as well as anyone looking to deepen their understanding of series expansions and singularities in complex functions.

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Homework Statement



I'm supposed to find the Laurent expansion of sin z/(z-1) at z=1.


The Attempt at a Solution



I thought about expanding the sine as a power series of (z-1) but I'm not so sure if that would be correct since the sine is a function of z and not z-1.
 
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put z=1+h,
then sin(1+h)/h.now you can expand it
 

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