How Do You Find the Multiplicative Inverse in \( Z_{360}[x] \)?

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SUMMARY

The discussion focuses on finding the multiplicative inverse of the polynomial \( f(x) = 30x^4 + 120x^2 + 240x + 7 \) in the ring \( R = Z_{360}[x] \). The solution involves solving the congruence \( 7a_0 \equiv 1 \pmod{360} \) using the Euclidean algorithm or inspection. The inverse is determined to be \( 7^{-1} \equiv 103 \pmod{360} \), demonstrating that small integers can yield results efficiently within a few attempts.

PREREQUISITES
  • Understanding of polynomial rings, specifically \( Z_{360}[x] \)
  • Knowledge of modular arithmetic and congruences
  • Familiarity with the Euclidean algorithm for finding inverses
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of polynomial rings, particularly \( Z_n[x] \)
  • Learn the detailed steps of the Euclidean algorithm for finding multiplicative inverses
  • Explore examples of finding inverses in other modular systems, such as \( Z_{12} \) or \( Z_{100} \)
  • Investigate the application of the Extended Euclidean Algorithm in polynomial contexts
USEFUL FOR

Mathematicians, students studying abstract algebra, and anyone interested in modular arithmetic and polynomial inverses will benefit from this discussion.

corkycorey101
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How would you find the multiplicative inverse of the following?

Let $R=Z_{360}[x]$
Find the multiplicative inverse of $f(x)=30x^4+120x^2+240x+7$ in $R$.

Do you have to solve it using the Euclidean Algorithm? If so, I'm not sure how to do that.
This problem has me stumped.

Any help is much appreciated.
Thanks!
 
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corkycorey101 said:
How would you find the multiplicative inverse of the following?

Let $R=Z_{360}[x]$
Find the multiplicative inverse of $f(x)=30x^4+120x^2+240x+7$ in $R$.

Do you have to solve it using the Euclidean Algorithm? If so, I'm not sure how to do that.
This problem has me stumped.

Any help is much appreciated.
Thanks!

Hi corkycorey101! Welcome to MHB! ;)

Let the multiplicative inverse be $f^{-1}(x)=a_n x^n + ... + a_0$.
Then:
$$7a_0 \equiv 1 \pmod{360}\\
240a_0 + 7a_1 \equiv 0 \pmod{360}\\
...
$$

To solve $7a_0 \equiv 1$, we could apply the Euclidean algorithm, but let's try inspection first.
If we divide $360 + 1$ by $7$, the remainder is $4$.
If we divide $2\cdot 360 + 1$ by $7$, the remainder is $0$.
So:
$$7^{-1} \equiv \frac{2\cdot 360 + 1}{7} \equiv 103 \pmod{360}$$
Generally, small as $7$ is, we can be sure to find sufficient information within 3 tries.
 

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