How Do You Integrate 2x sin(x^2) dx?

[teng125]

may i know how to integ [2x sin (x^2) dx]??the answer is -cos(x^2)

thanx...

 

[what]

use the subsititution u= x^2

 

[marlon]

may i know how to integ [2x sin (x^2) dx]??the answer is -cos(x^2)
thanx...

$$\int 2xsin(x^2)dx = \int sin(x^2) dx^2 = -cos(x^2)$$

The clue is that

$$2xdx = dx^2$$

marlon

edit : which is basically the same as what What has stated :)

 

[teng125]

oh...okkk...thanx...

 

[scholzie]

oh...okkk...thanx...

Haha, you don't sound to sure on that. Does it make sense?