How Do You Make a Complex Denominator Real in a Fractional Expression?

  • Thread starter Thread starter kelp
  • Start date Start date
Click For Summary
SUMMARY

This discussion focuses on simplifying a fractional expression with a complex denominator consisting of four terms, including imaginary components. The denominator is expressed as (1/jwC + R3 + jwL + R2). To make the denominator real, the technique involves multiplying by the complex conjugate, which in this case is (R3 + R2) - j(wC + wL). This method is applicable regardless of the number of terms, as demonstrated through examples that illustrate the separation of real and imaginary parts.

PREREQUISITES
  • Understanding of complex numbers and their conjugates
  • Familiarity with algebraic manipulation of fractions
  • Knowledge of imaginary numbers and their properties
  • Basic skills in expanding and factoring expressions
NEXT STEPS
  • Study the properties of complex conjugates in detail
  • Learn techniques for simplifying complex fractions
  • Explore advanced algebraic methods for handling multiple terms in denominators
  • Practice problems involving real and imaginary components in expressions
USEFUL FOR

Mathematics students, educators, and anyone involved in engineering or physics who needs to simplify complex expressions in their work.

kelp
Messages
9
Reaction score
0
Hello,
I am trying to simplify a fractional expression with four terms on the bottom, two of the terms are imaginary. How would I go about making the denominator real?
The denominator is as follows:
(1/jwC + R3 + jwL + R2)
The j is the imaginary number. Everything else is a constant. I know with two terms, you can just multiply by the complex conjugate. Not sure how to do it with four terms.
 
Physics news on Phys.org
It is no different with four terms.

The complex conjugate of (R3+R2)+j(wC+wL) is (R3+R2)-j(wC+wL)
 
Exactly what danago has said, when you're shown the technique of making the denominator of a complex number a+ib real by multiplying by its complex conjugate a-ib, the a and b can stand for any real number (however complicated).

For example, if a=x+y+1 and b=x^2+y^2+2 then the complex number

x+y+1+i(x^2+y^2+2) should be multiplied by its complex conjugate x+y+1-i(x^2+y^2+2) to obtain a^2+b^2 or (x+y+1)^2+(x^2+y^2+2)^2.

Now, the same complex number could have its real and imaginary parts split up, for example the above could be expressed as

x(1+ix)+y(1+iy)+2i+1

Now in this case it is less evident what the complex conjugate should be. You need to always expand, then collect the real terms and the imaginary terms separately. In other words, expand, then factorize out the i and all those terms that go with it are the imaginary terms while those without an i factorized out are the real terms. (if that makes any sense).
 
Thanks guys!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
710
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K