How do you multiply rational equations with multiple numerators?

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Homework Help Overview

The discussion revolves around multiplying rational equations that feature multiple numerators. The original poster presents a specific example involving two rational expressions and seeks clarification on the multiplication process without requesting a complete solution.

Discussion Character

  • Exploratory, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the multiplication of rational expressions, with one suggesting a formula for multiplying fractions. Others mention cross multiplication and express uncertainty about the original poster's intent regarding the operation.

Discussion Status

The conversation is ongoing, with various interpretations of the multiplication process being explored. Some participants provide guidance on potential methods, while others question whether the suggested approaches align with the original poster's question.

Contextual Notes

There is a mention of potential confusion regarding the setup of the rational expressions, particularly concerning the denominators and their forms. The original poster has requested not to receive direct answers, indicating a desire for understanding rather than completion of the problem.

JerryClower
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How do you multiply an equation that has 2 or more numerators. such as :

8x + 8 x - 1
______ X _______
X2 - 2x + 1 2x + 2




And don't say anything like, "I'm not doing your homework for you" or anything stupid like that. I just want to know how to do it, not the answer.
 
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[tex]\frac{A}{B} \times \frac{C}{D} = \frac{A \times C}{B \times D}[/tex]

Does that help?
 
You must cross multiply, if I'm looking at this correctly.
So if A/B x C/D => A x D=B x C

So:
8x + 8 x - 1
______ X _______
X2 - 2x + 1 2x + 2
(Yeah, I just copied that. I'm assuming that B has an x2on the bottom)

(8x + 8)(2x+2)=(x2 - 2x)(x - 1)
Now combine like terms, and solve for x. You will probably have to factor.
 
GreatEscapist said:
You must cross multiply, if I'm looking at this correctly.
So if A/B x C/D => A x D=B x C
You're thinking of: if A/B = C/D, then A x D = B x C

This may or may not be what the OP meant.
 

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