How Do You Prove De Morgan's Law for Union and Complement?

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SUMMARY

The discussion focuses on proving De Morgan's Laws, specifically the identity (A U B)' = A' ∩ B'. Participants clarify the logical steps required to demonstrate this relationship using set theory and mathematical logic. Key points include the necessity of starting from axioms in mathematical logic to validate the proof without circular reasoning. The conversation emphasizes the importance of precise definitions and logical structure in mathematical proofs.

PREREQUISITES
  • Understanding of set theory concepts, particularly unions and intersections
  • Familiarity with De Morgan's Laws in both set theory and logic
  • Basic knowledge of mathematical logic and axiomatic systems
  • Ability to manipulate logical statements and quantifiers
NEXT STEPS
  • Study the axioms of mathematical logic to understand foundational proofs
  • Explore additional examples of De Morgan's Laws in set theory
  • Learn about logical equivalences and their applications in proofs
  • Practice constructing proofs using direct and indirect methods in set theory
USEFUL FOR

Students of mathematics, particularly those studying set theory and mathematical logic, as well as educators seeking to enhance their teaching of proof techniques.

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Homework Statement



Prove De Morgan's Laws (only (A U B)' = A' n B' part)

Homework Equations



(A U B)' = A' n B'

The Attempt at a Solution



I used this
x does not belong to (A U B)
x belongs to A' and B'
x belongs to A' n B'

now opposite

x belongs to A' n B'
x belogns to A' and B'
x does not belong to A and B

and that's it.
how can this x does not belong to A and B can be changed into
x does not belong to (A U B)' ?

all these proving things are confusing..they are too obvious and that's why i can not do this properly how silly..
Any tips that can be used when solving this kind of questions?

Thankyou!
 
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(x \in A' \cap B') \Rightarrow \neg(x \in A)\wedge \neg (x \in B) = \neg[ (x \in A) \vee (x \in B) ] \Rightarrow (x \in (A \cup B)')

Does that make sense?
 
@dx - you are using demorgans law to prove demorgans law...

You used that form of the law that applies to mathematical logic, to get the same law in a different form in set theory..

So that proof is void
 
@dx - you are using demorgans law to prove demorgans law...

You used that form of the law that applies to mathematical logic, to get the same law in a different form in set theory..

So that proof is void
 
How can you prove anything if you're not allowed to use logic?
 
you can use logic. What i was talking about was a branch of mathematics - mathematical logic. You have to start from the axioms and prove the law that u have used in your proof. Start from the axioms of 'Mathematical Logic', and use those to prove it. It can be proved, but u must do it. Once that is done, rest follows

What you have done is use DeMorgan's Law in ML to prove the same in set theory. That is where u are wrong.
 
you can use logic. What i was talking about was a branch of mathematics - mathematical logic. You have to start from the axioms and prove the law that u have used in your proof. Start from the axioms of 'Mathematical Logic', and use those to prove it. It can be proved, but u must do it. Once that is done, rest follows

What you have done is use DeMorgan's Law in ML to prove the same in set theory. That is where u are wrong.
 
what is this \neg stand for?
 
385sk117 said:

Homework Statement



Prove De Morgan's Laws (only (A U B)' = A' n B' part)

Homework Equations



(A U B)' = A' n B'

The Attempt at a Solution



I used this
x does not belong to (A U B)
x belongs to A' and B'
x belongs to A' n B'
Very good but more precisely: "Let x belong to (A U B)'. Then x does not belong to A U B and so is not in A and is not in B. Therefore x is in A' and x is in B'. Then x is in A' n B'.

now opposite

x belongs to A' n B'
x belogns to A' and B'
x does not belong to A and B
Let x be in A' n B'. Then x is in A' and in B'. Since x is in A', x is not in A. Since x is in B', x is not in B. If x were in A U B, it would have to be in either A or B. Since it is not, it is not in A U B and so is in A' U B'.

and that's it.
how can this x does not belong to A and B can be changed into
x does not belong to (A U B)' ?

all these proving things are confusing..they are too obvious and that's why i can not do this properly how silly..
Any tips that can be used when solving this kind of questions?

Thankyou!
 
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