How Do You Prove the Bessel Identity J-3/2(x)?

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Discussion Overview

The discussion revolves around proving the Bessel identity for the function \( J_{-3/2}(x) \). Participants explore various approaches to establish this identity, including the use of series representations and properties of the gamma function. The scope includes mathematical reasoning and technical explanations related to Bessel functions and their properties.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant, Alan, expresses difficulty in proving the identity for \( J_{-3/2}(x) \) and mentions the negative value of the gamma function for \( n=0 \) as a complication.
  • Another participant suggests verifying that the right-hand side of the identity satisfies Bessel's differential equation and has the correct initial values, implying this could establish the identity without needing a series representation.
  • Alan later reflects on the properties of the gamma function, noting the different formulas applicable for positive and negative values of \( n \), and acknowledges a realization about applying these formulas in his calculations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach to prove the identity. There are multiple viewpoints on how to tackle the problem, and Alan's initial confusion highlights the complexity of the topic.

Contextual Notes

Alan's struggle with the gamma function's behavior for different values of \( n \) and the implications for series representation are noted, but the discussion does not resolve these issues.

yungman
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I have been working on this for a few days and cannot prove this:

J-3/2 (x)=[tex]\sqrt{\frac{2}{\pi x}}[/tex][[tex]\frac{-cos(x)}{x}[/tex] - sin(x) ]

Main reason is [tex]\Gamma[/tex](n-3/2+1) give a negative value for n=0 and possitive value for n=1,2,3... I cannot find a series representation of this gamma function.


Please advice me how to solve this problem. This is not a school homework.

thanks a million

Alan
 
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Maybe instead of the series representation for the Bessel function: show that your right-hand side satisfies Bessel's differential equation, and has the proper initial values, so that it therefore equals the Bessel function required.
 
yungman said:
Main reason is [tex]\Gamma[/tex](n-3/2+1) give a negative value for n=0 and possitive value for n=1,2,3... I cannot find a series representation of this gamma function.


Please advice me how to solve this problem. This is not a school homework.

thanks a million

Alan


For n > 0 we apply this formula
[tex]\Gamma (n+1) = n \Gamma (n)[/tex]

but if n < 0 we apply this formula
[tex]\Gamma (n)=\frac{\Gamma (n+1)}{n}[/tex]
 
matematikawan said:
For n > 0 we apply this formula
[tex]\Gamma (n+1) = n \Gamma (n)[/tex]

but if n < 0 we apply this formula
[tex]\Gamma (n)=\frac{\Gamma (n+1)}{n}[/tex]

I know this formula! This is embarassing! How can I over looked this and spent 3 days on this...Even joined two more math forums! I even plug in the numbers and hope this is not that simple! I use

[tex]\Gamma (-3/2)=\frac{\Gamma (-1/2)}{-3/2}[/tex] all the time! Just never try with n in it!

Thanks a million...Even though you make me look really really bad!

Cheers.
Alan
 

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