How Do You Prove the Bessel Identity J-3/2(x)?

  • Context: Graduate 
  • Thread starter Thread starter yungman
  • Start date Start date
  • Tags Tags
    Bessel Identity
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 5K views
yungman
Messages
5,741
Reaction score
291
I have been working on this for a few days and cannot prove this:

J-3/2 (x)=[tex]\sqrt{\frac{2}{\pi x}}[/tex][[tex]\frac{-cos(x)}{x}[/tex] - sin(x) ]

Main reason is [tex]\Gamma[/tex](n-3/2+1) give a negative value for n=0 and possitive value for n=1,2,3... I cannot find a series representation of this gamma function.


Please advice me how to solve this problem. This is not a school homework.

thanks a million

Alan
 
Last edited:
Physics news on Phys.org
Maybe instead of the series representation for the Bessel function: show that your right-hand side satisfies Bessel's differential equation, and has the proper initial values, so that it therefore equals the Bessel function required.
 
yungman said:
Main reason is [tex]\Gamma[/tex](n-3/2+1) give a negative value for n=0 and possitive value for n=1,2,3... I cannot find a series representation of this gamma function.


Please advice me how to solve this problem. This is not a school homework.

thanks a million

Alan


For n > 0 we apply this formula
[tex]\Gamma (n+1) = n \Gamma (n)[/tex]

but if n < 0 we apply this formula
[tex]\Gamma (n)=\frac{\Gamma (n+1)}{n}[/tex]
 
matematikawan said:
For n > 0 we apply this formula
[tex]\Gamma (n+1) = n \Gamma (n)[/tex]

but if n < 0 we apply this formula
[tex]\Gamma (n)=\frac{\Gamma (n+1)}{n}[/tex]

I know this formula! This is embarassing! How can I over looked this and spent 3 days on this...Even joined two more math forums! I even plug in the numbers and hope this is not that simple! I use

[tex]\Gamma (-3/2)=\frac{\Gamma (-1/2)}{-3/2}[/tex] all the time! Just never try with n in it!

Thanks a million...Even though you make me look really really bad!

Cheers.
Alan