How Do You Solve a Combination Lens Problem in Optics?

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Homework Help Overview

The problem involves a combination of lenses in optics, specifically a convex lens followed by a concave lens. The original poster presents a scenario where an object is placed in front of the convex lens, and the task is to determine the position and nature of the final image formed by the system of lenses.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the lens formula to find the image position for the first lens but expresses uncertainty about how to proceed with the second lens due to the image position relative to the second lens. Other participants engage by suggesting calculations based on the image position from the first lens and questioning the correctness of the approach.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the image positions and the implications for the second lens. Some calculations have been shared, but there is no explicit consensus on the correctness of the approaches taken.

Contextual Notes

Participants are navigating the complexities of combining lenses and the implications of image positions, with some uncertainty about the nature of the images formed and how they relate to the subsequent lens.

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Homework Statement



An object is placed 400 mm in front of a convex lens of focal length 80 mm. Find the position of the image formed. State the nature of this image.

A second concave lens of focal length 25 mm is placed 80 mm behind the first convex lens. Find the position of the final image formed and state its nature.

The Attempt at a Solution



[itex]\frac{1}{U} + \frac{1}{V} = \frac{1}{F}[/itex]

[itex]\frac{1}{V} = \frac{1}{80} - \frac{1}{400}[/itex]

[itex]V = 100 mm[/itex]



So the Image from lens one forms 100 mm to the right of lens one. BUT, lens 2 is only 80 mm to the right of lens 1. I don't know what to do here since no image has been formed to create a new object for lens 2.

Any help?
 
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Which means the Object´s image will appear to the right (or behind) of the concave lense.
80-100= -20
U=-20 solve for V
 
[itex]\frac{1}{-20} + \frac{1}{V_{2}} = \frac{1}{F}[/itex]

[itex]\frac{1}{V_{2}} = \frac{1}{20} - \frac{1}{25} = \frac{1}{100}[/itex]

[itex]V = 100[/itex]
 
Is this correct?
 

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