How Do You Solve a Physics Problem Involving Forces and Motion?

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Homework Help Overview

The problem involves analyzing forces and motion related to a lawn mower being pushed at a constant speed. It requires drawing a free-body diagram and calculating various forces, including friction and normal force, as well as determining the force needed to accelerate the mower.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster seeks assistance with multiple parts of the problem, including drawing a free-body diagram and calculating forces. Some participants inquire about the attempts made by the original poster and suggest breaking down the forces involved.

Discussion Status

Participants are engaging in a dialogue about the calculations needed for the problem. Some have offered insights into the components of the forces involved, while others are questioning the original poster's progress and understanding of the concepts.

Contextual Notes

The original poster mentions this problem is from a practice test for Pharmacy school, indicating a potential time constraint or pressure related to exam preparation.

fishert16
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Cant figure out how to do this problem??

A person pushes a 14kg lawn mover at constant sped with a force of 88N directed along the handle, which is at an angle of 45 degress to the horizontal. (a) draw the Free-body diagram showing all forces acting on the mower. (b) Calculate the horizontal friction force on the mower, then (c) the normal force exerted vertically upward on the mower by the ground. (d) What force must the person exert on the lawn mower accelerate it from rest to 1.5m/s in 2.5 seconds, assuming the same friction force?

This is a problem on my practice PCAT test for Pharmacy school. And its been a while since I have had physics so any help would be appreciated.

Thanks
 
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Well, what have you done? Have you drawn a free body diagram at least? Which parts of the question have you attempted?
 
Because the angle of the handle is 45 degrees, the force along the handle of 88N can be broken up into a horizonal force or square root of 2x88; and a vertical downward force of the same amount. I.e. 1.414 x 88 = 124.4 N.

Nelson
 
Nelson,

er, that's close but sin and cos 45 are actually= sqrt(2)/2=1/sqrt(2)=.707

On the other post, I mentioned what the Normal force is, so can you calculate it? Hint: weight plus vertical component of push but directed upwards. So what is weight?
 

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