How do you solve and plot inequalities with multiple variables?

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Discussion Overview

The discussion revolves around solving and plotting inequalities with multiple variables, specifically focusing on the inequalities $$2

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses uncertainty about how to find points to plot for the inequalities $$2
  • Another participant clarifies that the region defined by $$2
  • There is a question about whether the graph would intersect the $y$-axis diagonally through the points 2 and 6.
  • Participants discuss the method of graphing the lines $$x=2$$ and $$x=6$$ with dashed lines due to the strict inequalities.
  • There is a proposal to shade the region between the lines based on the inequalities, with one participant suggesting that the area to the right of $$x=2$$ and to the left of $$x=6$$ should be shaded.
  • Another participant confirms this shading approach, indicating that the shaded region represents all values of $$x$$ in the interval $(2,6)$.

Areas of Agreement / Disagreement

Participants generally agree on the method of graphing the inequalities and the interpretation of the shaded region, but there is some uncertainty regarding the initial plotting of points for the inequalities $$2

Contextual Notes

Some participants express uncertainty about the initial steps in plotting the inequalities, and there may be missing assumptions regarding how to approach the graphing of multiple inequalities simultaneously.

ai93
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I have the inequalities $$2<x<6,\quad 1<y<5,\quad y-2\le2x, \quad-2y\ge8-4x$$ I have to solve these and plot it in a graph and show the region where they satisfy. I understand you have to find the common area and shade it.

How do you find the points to plot for $$2<x<6\quad and\quad 1<y<5$$

I think I have solved $$y-2\le2x\quad and -2y\ge8-4x$$ to $$y\le2x+2\quad and \quad y\le-4+2x$$ I am just unsure on the first two. Will making a X and Y table help to find the points?
 
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Well, the region $2<x<6$ contains all the points in the $x,y$-plane where the $x$-component lies between $2$ and $6$ (both not included).
 
Siron said:
Well, the region $2<x<6$ contains all the points in the $x,y$-plane where the $x$-component lies between $2$ and $6$ (both not included).

If i made a graph, would it go through the $y$ axis diagonal through the points $2$ and $6$?
 
mathsheadache said:
If i made a graph, would it go through the $y$ axis diagonal through the points $2$ and $6$?

For the inequality $2<x<6$, I would begin by graphing the lines $x=2$ and $x=6$ with dashed lines since the inequality is strict on both sides of $x$. Now you have divided the plane into 3 regions. which of these regions should you shade?
 
MarkFL said:
For the inequality $2<x<6$, I would begin by graphing the lines $x=2$ and $x=6$ with dashed lines since the inequality is strict on both sides of $x$. Now you have divided the plane into 3 regions. which of these regions should you shade?

Because it is x>2 is greater than, I shade everything to the right. And because x<6 is less than, shade everything to the left? I will be left with a shaded region in between 2 and 6?
 
mathsheadache said:
Because it is x>2 is greater than, I shade everything to the right. And because x<6 is less than, shade everything to the left? I will be left with a shaded region in between 2 and 6?

Yes, good! (Sun)

That's what $2<x<6$ means...any value of $x$ on the interval $(2,6)$, i.e., any value of $x$ in between 2 and 6, but not including 2 and 6. :D

So, the region you have shaded contains all the points in the plane for which the $x$-coordinate satisfies the given compound inequality.
 

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