How Do You Solve for v in Physics Equations?

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The discussion revolves around solving for the variable v in a physics equation related to optics. The initial attempt at a solution yielded a value of -1.06 cm, indicating the position relative to a wall. Participants noted the absence of a clear problem statement, which hindered the ability to provide assistance. Eventually, the original poster acknowledged a mistake in their calculations. The conversation highlights the importance of clearly presenting problems in physics for effective collaboration.
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Homework Statement



the ans is B for this question

Homework Equations





The Attempt at a Solution


my working is 1.59/2.0 + 1/v = (modulus of 1-1-59) /( -4 )
my v is -1.06cm. which is 1.06cm to the right from the tleft wall of plastic ball
 
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desmond iking said:

Homework Statement



the ans is B for this question

Homework Equations





The Attempt at a Solution


my working is 1.59/2.0 + 1/v = (modulus of 1-1-59) /( -4 )
my v is -1.06cm. which is 1.06cm to the right from the tleft wall of plastic ball

What question? Did you forget to attach something
 
desmond iking said:

Homework Statement



the ans is B for this question

Homework Equations





The Attempt at a Solution


my working is 1.59/2.0 + 1/v = (modulus of 1-1-59) /( -4 )
my v is -1.06cm. which is 1.06cm to the right from the tleft wall of plastic ball

It's going to awfully hard for anyone to give you any help based on the total lack of a problem statement.
 
phinds said:
It's going to awfully hard for anyone to give you any help based on the total lack of a problem statement.

her's the question
 

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you could draw a ray diagram to locate the image.
 
Sorry, I have found my mistake finally
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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