How Do You Substitute in a Polynomial Function?

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Homework Help Overview

The discussion revolves around substituting values into a polynomial function, specifically the function f(x) = x^2 - 4x, and determining the expression for g(x) when substituting x + 2 into f. Participants explore the correct method for substitution and the implications of their attempts.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss how to correctly substitute (x + 2) into f(x) and question the original poster's attempt, which seems to misunderstand the substitution process. There are suggestions to clarify the substitution technique and to use different variables to avoid confusion.

Discussion Status

Some participants have provided guidance on how to approach the substitution correctly, emphasizing the need to replace every instance of x in the function with (x + 2). There is an ongoing exploration of the correct polynomial form after substitution, with some participants noting mistakes in earlier attempts.

Contextual Notes

There is a focus on ensuring that all instances of x are substituted correctly, and some participants suggest using a temporary variable to minimize errors. The discussion reflects a learning process with varying levels of understanding regarding function substitution.

caprija
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If f(x)=x^2 - 4x, determine an expression for g(x)

g(x) = f(x + 2)

How would I substitute f(x) when they are separated?

my attempt

g(x) = x^2 - 4x (x + 2)
 
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OK, first are you happy with this one: we have f(x) = x^2 - 4x, what is f(a)?
(Answer: f(a) = a^2 - 4a. i.e. you just plug a into wherever x used to appear. It does NOT mean "f(a) = f(x) * a", which is similar to what you seem to have done in your attempt.)

Now, use the same technique for f(x+2). We just plug (x+2) into wherever x used to appear. What do you reckon the answer should be?

Once you have written f(x+2) as a polynomial, then we can call it g(x), or h(x) or y(x). So the "g(x) = " bit isn't that important.
 
electricsheep said:
OK, first are you happy with this one: we have f(x) = x^2 - 4x, what is f(a)?
(Answer: f(a) = a^2 - 4a. i.e. you just plug a into wherever x used to appear. It does NOT mean "f(a) = f(x) * a", which is similar to what you seem to have done in your attempt.)

Now, use the same technique for f(x+2). We just plug (x+2) into wherever x used to appear. What do you reckon the answer should be?

Once you have written f(x+2) as a polynomial, then we can call it g(x), or h(x) or y(x). So the "g(x) = " bit isn't that important.

Ok so the solution would be:

(x + 2) ^2 - 4x
x^2 + 4x - 4X + 4

answer: x^2 + 4
 
caprija said:
Ok so the solution would be:

(x + 2) ^2 - 4x
x^2 + 4x - 4X + 4

answer: x^2 + 4

Almost. You skipped substituting (x+2) in for one of your x's.
 
It will be a lot easier if you use "a+2" instead of "x+2" then switch it back so you know you swapped them all. Much harder to make a mistake.
 
f(x)=x^2 -4x

f(2) = 2^2 -4*2
f(3) = 3^2 -4*3
f(m) = m^2 -4*m
whatever is inside those parenthesis next to f, you're going to substitute for every x inside the original function.

f( :approve: ) = :approve: ^2 -4*:approve:


What helps sometimes is to just put in parenthesis where x is, then go back and fill them in...

(____)^2 - 4*(____)

Then, put into those parenthesis whatever is f(HERE)
 

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