How Do You Validate the Second Part of This System of Linear Equations?

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Homework Help Overview

The discussion revolves around a system of linear equations involving variables x, y, and z, with a focus on determining the value of λ and validating a maximum value expression involving μ and trigonometric functions. The context is rooted in linear algebra and optimization.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the use of matrix methods to find λ and discuss the implications of the determinant of the coefficient matrix. There are attempts to validate a given maximum value expression, with some participants questioning the need for additional information regarding μ.

Discussion Status

Some participants have provided guidance on the necessity of determining μ alongside λ to ensure the system has solutions. There is ongoing exploration of the optimization problem, with one participant indicating they have made progress in validating the maximum value expression.

Contextual Notes

Participants note that the system has infinite solutions, and there is an emphasis on the relationship between λ and μ in the context of the equations provided. The discussion includes references to constraints and optimization methods relevant to the problem.

AGNuke
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If the system of Linear Equations
[tex]x+y+z=6[/tex]
[tex]x+2y+3z=14[/tex]
[tex]2x+5y+\lambda z=\mu[/tex]
has infinite number of solution in x, y, z

I need to find out two things
1. The value of λ
2. Maximum value of [tex](\mu x+\lambda y-20z)sin^2\theta+(\lambda x+\mu y+64z)cos2\theta, \theta \in \mathbb{R}[/tex] is 272

I used the Matrix method of AX=B to find out λ by solving for A=0; I got the answer 8, and it is correct.

Now my catch is to validate the second question. It is given true, I just need to validate. I tried to solve it with the three existing equations but I was unable to get answer.
 
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AGNuke said:
If the system of Linear Equations
[tex]x+y+z=6[/tex]
[tex]x+2y+3z=14[/tex]
[tex]2x+5y+\lambda z=\mu[/tex]
has infinite number of solution in x, y, z

I need to find out two things
1. The value of λ
2. Maximum value of [tex](\mu x+\lambda y-20z)sin^2\theta+(\lambda x+\mu y+64z)cos2\theta, \theta \in \mathbb{R}[/tex] is 272

I used the Matrix method of AX=B to find out λ by solving for A=0; I got the answer 8, and it is correct.
That isn't quite correct- first you haven't told us what "A" is! More important you mean det(A)= 0, not A= 0.

Now my catch is to validate the second question. It is given true, I just need to validate. I tried to solve it with the three existing equations but I was unable to get answer.
 
A is the coefficient matrix which is present when we try to solve the system of equations using matrix.

[tex]A=\begin{bmatrix}<br /> 1 &1 &1 \\ <br /> 1 & 2 &3 \\ <br /> 2 &5 &\lambda <br /> \end{bmatrix}[/tex]

and yes, I meant |A|=0, my bad.

Whatever that may be, I found out the value of λ and I need to find answer to my second question. I am on it, but haven't made progress.
 
AGNuke said:
A is the coefficient matrix which is present when we try to solve the system of equations using matrix.

[tex]A=\begin{bmatrix}<br /> 1 &1 &1 \\ <br /> 1 & 2 &3 \\ <br /> 2 &5 &\lambda <br /> \end{bmatrix}[/tex]

and yes, I meant |A|=0, my bad.

Whatever that may be, I found out the value of λ and I need to find answer to my second question. I am on it, but haven't made progress.

You also need to determine the value of μ (because if you don't have the correct value the system will have no solutions at all). Once you know λ and μ you have an optimization problem in the 4 variables x,y,z,θ, subject to linear restrictions on x,y,z. This can be tackled via Lagrange multiplier methods, or in some other way that handles constraints. At that point the problem is more suitable for the "Calculus and Beyond" Forum.

RGV
 
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μ can be determined by solving the three given equations, at which point, it returns the value 36.

We know λ and we know μ, I think we are good to go and find the answer.

UPDATE: I got my answer. I just found out y=4-2x and z=x+2; since the system has infinite solutions. I substituted y and z in the asked equation, got -8sin2θ + 272cos2θ. Then made sinθ=0 and cos2θ=1. Proved the statement right. :wink:
 
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