How Do You Write the Reaction Quotient Qc for This Reaction?

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SUMMARY

The reaction involving solid molybdenum (VI) oxide, gaseous xenon difluoride, liquid molybdenum (VI) fluoride, xenon gas, and oxygen gas requires a correct formulation of the reaction quotient Qc. The balanced reaction equation is MoO3(s) + 3XeF2(g) → MoF6(l) + 3Xe(g) + 3/2O2(g). The correct expression for Qc excludes solids and liquids, leading to Qc = [Xe]^3 [O2]^(3/2) / [XeF2]^3.

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  • Familiarity with the concept of reaction quotients
  • Knowledge of phase states in chemical reactions (solid, liquid, gas)
  • Basic skills in balancing chemical equations
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  • Explore the differences between Qc and Kc in chemical kinetics
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Can't figure this one out. Here's the problem.

Solid molybdenum (VI) oxide reacts with gaseous xenon difluoride to form liquid molybdenum(VI) fluoride, xenon gas, and oxygen gas. Write the Qc for this reaction.

I know Qc is products over reactants and pure liquids and solids are not included.

So this is what I came up with. Its wrong though.

Qc= [XeF2]3 / [Xe]3 [O2]

Any help would be great. Thanks.
 
Physics news on Phys.org
1. What is the balanced reaction equation?

2. If it is products over reactants, why do you have XeF2 - a reactant - in the numerator?
 

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