How does a buffer actually work?

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SUMMARY

A buffer solution consists of a weak acid and its conjugate base, which effectively resists changes in pH upon the addition of strong acids or bases. When a strong acid is introduced, the H+ ions react with the conjugate base (A-) to form more of the weak acid (HA), increasing its concentration and shifting the equilibrium to the right. Conversely, when a strong base is added, OH- ions react with H+ from the weak acid, decreasing HA and increasing A-, which shifts the equilibrium to the left. This dynamic equilibrium behavior is explained by Le Chatelier's principle.

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Buffer is a solution of weak acid and its conjugate base which resists the change in pH when strong acid/base is added to the solution.

But how does it work?

Consider,

HA + H2O ⇄ H3O+ + A-

When we add strong acid, the H+ from the strong acid reacts with the conjugate base A- to for HA. Hence, the concentration of HA increases while the concentration of A- decreases. According to Le Chatelier's principle the equilibrium reaction shifts to the right. So then won't the H3O+ concentration increase further? We want it to shift to the left right?

When we add strong base, the OH- reacts with H+ from the weak acid to form H2O. So concentration of HA decreases while the concentration of A- increases hence the reaction should shift towards the left, am I correct? It was given it shifts towards the right. How?Thanks!
 
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Kaushik said:
When we add strong acid, the H+ from the strong acid reacts with the conjugate base A- to for HA. Hence, the concentration of HA increases while the concentration of A- decreases. According to Le Chatelier's principle the equilibrium reaction shifts to the right.

No, it shifts to the left and stops there.
 

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