How Does A.H. Pfund's Method Determine the Refractive Index of Glass?

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SUMMARY

A.H. Pfund's method for determining the refractive index of glass involves measuring the diameter of a dark circle created by diverging rays from a point source. The refractive index (n) is calculated using the formula n=(1+(16t^2)/d^2)^(1/2), where 't' is the thickness of the glass slab and 'd' is the diameter of the dark circle. For a slab thickness of 0.06 cm and a refractive index of 1.52, the diameter of the dark circle is calculated to be 2.09×10-2 m. The discussion highlights that violet light, having a higher refractive index, is dispersed more than red light, affecting the critical angle and the appearance of the halo.

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Homework Statement


An A.H. Pfinds's method for measuring the index of refraction of glass is illustrated in the figure. One face of a slab of thickness t is painted white, and a small hole scraped cleat at point P serves as a source of diverging rays when the slab is illuminated from below. Ray PBB' strikes the clear surface at the critical angle and is totally elected, as are rays such as PCC'. Rays such as PAA' emerge from the clear surface. On the painted surface, there appears a dark circle of diameter d surrounded by an illuminated region, or halo.

diagram: https://dl.dropbox.com/u/77575413/68.png

Part A:
The equation for n in terms of the measured quantities d and t. is n=(1+(16t^2)/d^2)^(1/2)

Part B:
The diameter of the dark circle if n=1.52 for a slab of 0.06 cm thick is 2.09×10(-2)m

Part C:
If white light is used, dispersion causes the critical angle to depend on color. Is the inner edge of the white halo tinged with red light or with violet light explain.

Homework Equations



n=(1+(16t^2)/d^2)^(1/2)

The Attempt at a Solution



I was able to do part A and B but I am not sure about Part C.

I said the white halo is tinged with violet light since violet light has a higher index of refraction. Is this true or did I mess up.
 
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