How Does a Missing Component in the Feedback Loop Affect the Transfer Function?

[Femme_physics]

I'm confused by the fact there's nothing in the feedback loop here

http://img706.imageshack.us/img706/6075/feedbackloop.jpg


For instance, if I had "H1" in the feedback loop I'd do

C/R = (Gcs x Gps) / (1+H1)

But since I don't have H1... is it simply

C/R = (Gcs x Gps) / 1 = Gcs x Gps

?

 

[I like Serena]

You have 1 loop.
And yes, you don't have H1 in the returning part of the loop, so you can simply leave that out.
But you still have Gcs and Gps in the forward part of the loop.
Shouldn't you put those in the denominator?

 

[Femme_physics]

I seem to have completely forgot control theory. Allow me to slap myself twice in the face silly and strap myself to the chair with old materials.

Sorry to have bothered you for trifles, sensei :)

 

[I like Serena]

I seem to have completely forgot control theory. Allow me to slap myself twice in the face silly and strap myself to the chair with old materials.

Sorry to have bothered you for trifles, sensei :)

Trifles are better than nothing. ;)

Can I slap you a couple of times too as long as you are strapped to a chair anyway?