I How Does a Qubit Exist as Both 1 and 0 Simultaneously?

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Qubits exist in a quantum superposition, allowing them to represent both 1 and 0 simultaneously until measured. This phenomenon differs from classical bits, which are strictly either on or off. The concept of superposition is fundamental to quantum computing, enabling complex computations. For a deeper understanding, various resources and explanations are available online. Engaging with these materials can clarify how qubits function and their implications in quantum physics.
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QBITS binary state
I think 10 more IQ points would help me understand quantum physics at the level I'd like. That said, I'd like to know more about Qbits. I've watched several videos about them, and they say that they can be 1 and 0 at the same time. Is that just an analogy to the polarization of the old magnetic core, and on/off state of modern solid state bits, or is the actual physical state of a Qbit actually 1 and 0 at the same time due to superpositioning and then finally becomes binary when detected?
 
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Qbit state is a quantum superposition of two definite states.
 
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Googling something like 'how can a qbit hold multiple values' yields a wealth of simple explanations. Take your pick and ask specific questions.
 

Thread 'Angular Momentum Vector and Its Magnitude'

For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...
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