How Does Adding Heat Affect Pressure in a Sealed Steam Container?

[TheBelgiumWaff]

Homework Statement

Given: A sealed, rigid container (cannot change shape or size) containing steam at the shown conditions has heat added until it reaches the final shown state.

Determine: a) heat added, b) work performed, c) change in internal energy of the system, and d) final system pressure

Homework Equations

Q = W + Δu

Also given: T1= 200 deg C, mass = 10kg, volume = 1m^3 (for initial conditions)
T2 = 350 C (for final conditions)

The pressures I found in the thermo tables for the corresponding temperatures are:
P1 = 1554.9 KPa
P2 = 16529 KPa

The Attempt at a Solution

What I know is it's a saturated vapor system since it stated steam in the problem statement and closed system so no work is done.

From that I was able to answer b) W = 0 and c) Q = 0 + m(u1-u2) --> 10Kg(2594.2-2418.3) KJ/kg = 1759 KJ of internal energy. The u's I got from thermo tables.

The two I'm having a hard time with is a) the heat added to the system and d) final system pressure.

 

[CrazyNinja]

First of all, the "conditions" are not mentioned. But we can proceed nevertheless.

The OP answered (b) and (c). The answer of (a) is but the answer of (c). The answer to (d) can be obtained using the ideal gas equation.