How Does an Underground Oil Pocket Affect Gravity Measurements?

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SUMMARY

The discussion focuses on calculating the gravitational acceleration (g) above a subterranean oil pocket with a diameter of 1.30 km and a density of 8.10x10^3 kg/m^3. The user inquires whether to use the equation F = G (m1 + m2) / r^2 for this calculation. The correct approach involves applying the principles of gravitational attraction and considering the mass of the oil pocket to determine the percentage difference in gravitational acceleration compared to a uniform Earth model.

PREREQUISITES
  • Understanding of gravitational force equations, specifically F = G (m1 * m2) / r^2
  • Knowledge of density and its impact on mass calculations
  • Familiarity with gravitational acceleration concepts
  • Basic principles of geophysics related to subsurface structures
NEXT STEPS
  • Research the application of Newton's law of gravitation in geophysical contexts
  • Learn about the effects of subsurface density variations on gravitational measurements
  • Study the concept of gravitational anomalies and their implications in geology
  • Explore methods for calculating gravitational acceleration in non-uniform fields
USEFUL FOR

Geophysicists, engineers in oil exploration, and students studying gravitational effects related to subsurface structures will benefit from this discussion.

tavo0116
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Problem:
The center of a 1.30 km diameter spherical pocket of oil is 1.30 km beneath the Earth's surface.
Estimate by what percentage g directly above the pocket of oil would differ from the expected value of g for a uniform Earth? Assume the density of oil is 8.10x10^3 kg/m^3

Should I use the equation: F = G (m1 + m2) / r^2 ?
If not, which equation should I use?

Please help me to get started.

Thank you.
 
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Does this seem right way to find g and g'?
 

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