How Does Braking Affect the Temperature of Car Brakes?

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SUMMARY

The discussion focuses on calculating the increase in temperature of car brakes after a vehicle comes to a stop. A 758 kg car traveling at 25 m/s uses its 16 kg iron brakes to absorb energy, with the specific heat of iron being 450 J/kg·°C. The kinetic energy of the car, calculated using the formula 1/2 mv², is converted into heat energy (Q) that raises the temperature of the brakes. The change in temperature can be determined using the equation Q=mc(t1-t2).

PREREQUISITES
  • Understanding of kinetic energy calculations (1/2 mv²)
  • Knowledge of specific heat capacity (J/kg·°C)
  • Familiarity with heat transfer concepts
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate the kinetic energy of a moving vehicle using 1/2 mv²
  • Explore the concept of heat transfer in materials
  • Learn how to apply the specific heat formula Q=mc(t1-t2)
  • Investigate the thermal properties of different materials used in braking systems
USEFUL FOR

Physics students, automotive engineers, and anyone interested in the thermal dynamics of braking systems will benefit from this discussion.

Cortar
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A 758 kg car moving at 25 m/s brakes to a
stop. The brakes contain about 16 kg of iron
that absorb the energy.
What is increase in temperature of the
brakes? Assume the specific heat of iron is
450 J=kg ¢
± C. Answer in units of ±C.Q=mc(t1-t2)

Ok I have the mass of the brakes and the specific heat and I know you only have to solve for the change in temperature, so I all need is Q.
I know Q is measured in Joules and J=Newton x distance, but all I am given is the velocity of the car, nothing about time, distance, or Acceleration. So how do you figure the Q?
 
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Cortar said:
A 758 kg car moving at 25 m/s brakes to a
stop. The brakes contain about 16 kg of iron
that absorb the energy.
What is increase in temperature of the
brakes? Assume the specific heat of iron is
450 J=kg ¢
± C. Answer in units of ±C.


Q=mc(t1-t2)

Ok I have the mass of the brakes and the specific heat and I know you only have to solve for the change in temperature, so I all need is Q.
I know Q is measured in Joules and J=Newton x distance, but all I am given is the velocity of the car, nothing about time, distance, or Acceleration. So how do you figure the Q?

It comes to a stop so all the initial kinetic energy (1/2 mv^2) goes into heat. That's your Q
 

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